Answer:
Rutherford's experiment, also known as
supports the existence of neutrons and the nucleus.
Explanation:
In the above diagram, Rutherford was trying to explain his contributions using thin foils of gold and other metals as targets for alpha particles from a radioactive source.
He observed that the majority of particles penetrated the foil either undeflected or with only a slight deflection. But, every now and then an alpha particle was scattered(or deflected) at a large angle..
According to Rutherford, most of the atoms must be empty space. This explains why the majority of alpha particles passed through through the gold foil with little or no deflection. The atoms positive charges, Rutherford proposed are all concentrated in the Nucleus, <em>which</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>dense</em><em> </em><em>central</em><em> </em><em>core</em><em> </em><em>withi</em><em>n</em><em> </em><em>the</em><em> </em><em>atom</em><em>. </em>
Whenever an alpha particle came close to a nucleus in the scattering experiment, it experienced a large repulsive force and therefore a large deflection. Moreover, an alpha particle coming towards a nucleus would be completely repelled and its direction would be reversed. The positively charged particles in the Nucleus are called Protons.
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Answer:
Cs > Ba > Bi > Hf > Ta
Explanation:
The atomic radius of a chemical element defined as the distance between nucleus and electron from the center.
<u>The atomic number and atomic radius of given elements are:</u>
<u>Barium (Ba):</u>
Atomic number - (56)
Atomic radius - 268 pm
<u>Caesium (Cs) </u>
Atomic number - 55
Atomic radius - 343 pm
<u>Hafnium (Hf):</u>
Atomic number - 72
Atomic radius - 225 pm
<u>Bismuth (Bi):</u>
Atomic number - 83
Atomic radius - 230
<u>Tantalum (Ta):</u>
Atomic number - 73
Atomic radius - 220 pm
According to the given atomic radius the decreasing order of atomic radius is Cs > Ba > Bi > Hf > Ta.
Caesium has highest atomic radius among all even though lowest atomic number because the force of attraction between the nucleus and the outermost electron is low and outermost electron are loosely held.
Barium (Ba) has lower atomic number than Bismuth (Bi) but still atomic radius of Barium is high because moving across the periodic table atomic radius decreases as force of attraction between nucleus and outer electrons is high.
Bismuth (Bi) has higher atomic number that Hafnium (Hf), atomic radius of Bi is more than Hf.
Tantalum (Ta) have higher atomic number than Hafnium (Hf) but still have lower atomic radius as as force of attraction between nucleus and outer electrons is high.
Hence, the decreasing atomic radius is Cs > Ba > Bi > Hf > Ta.
Answer:
3-12 "group D" transition metals
Explanation:
All electron configurations that end in group D will be between groups 3-12. Specifically it would be group 8 because of the D8.