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bonufazy [111]
3 years ago
13

The first extra-solar planet around a main sequence star (i.e., not a neutron star or white dwarf) was found around the star 51

Pegasi in 1995. The large planet causes a measureable motion of the star around the center of mass of the system. Pegasi 51's orbital motion had a period of 4 days indicating a very large planet very close to the star. A large planet of mass M around a small star of mass 4M. The distance between planet and star is L. Both the planet and star will orbit around the center of mass of the system (marked by the red X).
Required:
Where is the center of mass of the star-planet system?
Physics
1 answer:
iogann1982 [59]3 years ago
8 0

Answer:

   r_{cm}= 1/5 L

Explanation:

To find the center of mass of the system let's use

        r_{cm} = \frac{1}{M} ∑ r_i x_i

where m is the total mass of the system

let's apply this expression to our case

       

Let's set the reference frame on the star

         r_{cm} = \frac{1}{M +4M} ( 4M 0 + M L)

         r_{cm} = \frac{1}{5} L

         r_{cm}= 1/5 L

Hey, the breast center is 1/5 of the distance between the star and the planet.

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most neutral atoms of fluorine have an atomic mass of 19 amu and an atomic number of 9. what are these atoms composed of
Usimov [2.4K]

Answer:

An atom of fluorine has the atomic number 9, and its mass number is 19 amu. Which of the following shows a neutral atom of fluorine? 16 protons and 14 electrons.

Explanation:

ITs 16 protins and 14 ELECTRONS

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4 years ago
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How is elevation shown on a topographic map?
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Answer:

contour lines

Explanation:

just looked at my notes and said contour lines

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Car B is being pushed by a force of 22000 N. If it has a mass of 1375 kg.,
Burka [1]

Answer:

a = 16 m/s²

General Formulas and Concepts:

<u>Dynamics</u>

Newton's Law of Motions

  • Newton's 1st Law of Motion: An object at rest remains at rest and an object in motion stays in motion
  • Newton's 2nd Law of Motion: F = ma (Force is equal to [constant] mass times acceleration)
  • Newton's 3rd Law of Motion: For every action, there is an equal and opposite reaction<u> </u>

Explanation:

<u>Step 1: Define</u>

<em>Identify variables</em>

[Given] F = 22000 N

[Given] m = 1375 kg

[Solve] a

<u>Step 2: Find Acceleration</u>

  1. Substitute in variables [Newton's 2nd Law of Motion]:                                 22000 N = (1375 kg)a
  2. Isolate <em>a</em>:                                                                                                            16 m/s² = a
  3. Rewrite:                                                                                                             a = 16 m/s²
5 0
3 years ago
An LC circuit is built with a 20 mH inductor and an 8.0 PF capacitor. The capacitor voltage has its maximum value of 25 V at t =
Margaret [11]

Answer:

a) the required time is 0.6283 μs

b) the inductor current is 0.5 mA

Explanation:

Given the data in the question;

The capacitor voltage has its maximum value of 25 V at t = 0

i.e V_m = V₀ = 25 V

we determine the angular velocity;

ω = 1 / √( LC )

ω = 1 / √( ( 20 × 10⁻³ H ) × ( 8.0 × 10⁻¹² F) )

ω = 1 / √( 1.6 × 10⁻¹³  )

ω = 1 / 0.0000004

ω = 2.5 × 10⁶ s⁻¹

a) How much time does it take until the capacitor is fully discharged for the first time?

V_m =  V₀sin( ωt )

we substitute

25V =  25V × sin( 2.5 × 10⁶ s⁻¹ × t )

25V =  25V × sin( 2.5 × 10⁶ s⁻¹ × t )

divide both sides by 25 V

sin( 2.5 × 10⁶ × t ) = 1

( 2.5 × 10⁶ × t ) = π/2

t = 1.570796 / (2.5 × 10⁶)

t = 0.6283 × 10⁻⁶ s

t = 0.6283 μs

Therefore, the required time is 0.6283 μs

b) What is the inductor current at that time?

I(t) = V₀√(C/L) sin(ωt)

{ sin(ωt) = 1 )

I(t) = V₀√(C/L)

we substitute

I(t) = 25V × √( ( 8.0 × 10⁻¹² F ) / ( 20 × 10⁻³ H ) )

I(t) = 25 × 0.00002

I(t) = 0.0005 A

I(t) = 0.5 mA

Therefore, the inductor current is 0.5 mA

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