When entering an expressway, in the acceleration lane you should: A search for a gap in traffic and adjust your speed to the spe
1 answer:
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(a)
The work-energy theorem states that the work done on the cheetah is equal to its change in kinetic energy:
where
m = 51.0 kg is the mass of the cheetah
u = 0 is the initial speed of the cheetah (zero because it starts from rest)
u = 31.7 m/s is the final speed
Substituting, we find
(b) 6.1 cal
The conversion between calories and Joules is
1 cal = 4186 J
Here the energy the cheetah needs is
Therefore we can set up a simple proportion
to find the equivalent energy in calories:
Answer:
L = 0.635m
Explanation:
This problem involves the concept of stationary waves in pipes. For pipes closed at one end,
The frequency f = nv/4L for n = 1,3,5....n
For pipes open at both ends
f = nv/2L for n = 1,2,3,4...n
Assuming the pipe is closed at one end and that velocity of sound is 343m/s in air. If we are right we will obtain a whole number for n.
The film solution can be found in the attachment below.
Answer:
30.22 hours
Explanation:
Given data:
A= l² = (2 x )² = 4 x
m²
Length 'L' = 5m
current '' = 2 A
density of free electrons 'n'= 8.5 x /m³
Current Density 'J' = / A
J= 2/4 x
J= 5 x A/m²
We can determine the time required for an electron to travel the length of the wire by
T= L/ Vd
Where,
L is length and Vd is drift velocity.
Vd can be defined by J/ n|q|
where,
n is the charge-carrier number density
|q| is is the charge carried by each charge carrier
=>1.6 x C
T= L/ Vd
Therefore,
T= L . n|q| / J
T= (4 x 8.5 x x |1.6 x
|)/5 x
T= 108800 seconds =>1813.33 minutes
Converting minute into hours:
T= 30.22 hours
Thus, time that is required for an electron to travel the length of the wire is 30.22 hours