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SashulF [63]
3 years ago
13

When entering an expressway, in the acceleration lane you should: A search for a gap in traffic and adjust your speed to the spe

ed of the traffic. B set the cruise control for highway speed. C make a complete stop and check traffic for a suitable gap. D get as close to the vehicle ahead as possible so you can merge into the same gap.
Physics
1 answer:
sattari [20]3 years ago
3 0

Answer:A

Explanation: search for a gap in traffic and adjust your speed to the speed of the traffic.

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According to Newton's Second Law of Motion, an object will accelerate if you apply what kind of force? Question 1 options: Frict
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An unbalanced force is required to accelerate an object according to Newton's Second Law of Motion.

<h3>What does Newton's Second Law of Motion state?</h3>

It states that the force applied to the object is equal to the product of mass and acceleration.

F = ma

  • An object will accelerate when the net force applied on the object is more than zero or unbalanced.
  • The acceleration is the change in the direction or speed of the object. To achieve acceleration the force must be greater in a direction.

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Therefore, an unbalanced force is required to accelerate an object according to Newton's Second Law of Motion.

Learn more about Newton's Second Law of Motion.:

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If a small number of tree frogs migrate to a mat of vegetation that is already home to an established population of tree frogs a
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In the two-slit experiment, monochromatic light of frequency 5.00 × 1014 Hz passes through a pair of slits separated by 2.20 × 1
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Explanation:

It is given that,

Frequency of monochromatic light, f=5\times 10^{14}\ Hz

Separation between slits, d=2.2\times 10^{-5}\ m

(a) The condition for maxima is given by :

d\ sin\theta=n\lambda

For third maxima,

\theta=sin^{-1}(\dfrac{n\lambda}{d})

\theta=sin^{-1}(\dfrac{n\lambda}{d})

\theta=sin^{-1}(\dfrac{nc}{fd})  

\theta=sin^{-1}(\dfrac{3\times 3\times 10^8\ m/s}{5\times 10^{14}\ Hz\times 2.2\times 10^{-5}\ m})  

\theta=4.69^{\circ}

(b) For second dark fringe, n = 2

d\ sin\theta=(n+1/2)\lambda

\theta=sin^{-1}(\dfrac{5\lambda}{2d})

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\theta=sin^{-1}(\dfrac{5\times 3\times 10^8}{2\times 2.2\times 10^{-5}\times 5\times 10^{14}})

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Hence, this is the required solution.

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3 years ago
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