Penelope works as a lifeguard at the neighborhood pool. The chart shows
1 answer:
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<u>Answer</u>:
The vertices are:
A' = (-3, -3)
B' = (3, -3)
C' = (3, 3)
D' = (-3, 3)
The ratio of area of larger square to smaller square is 9:1
<u>Step-by-step explanation:</u>
Given:
A 2 x 2 square is centered at the origin.
So, the center of the square is (0, 0)
Since it is 2 x 2 square, the side of the square is 2 units.
So, the vertices of the 2 x 2 square are A (-1, -1), B(1, -1), C(1. 1), D(-1, 1)
The above square is dilated by a factor of 3.
Let's name the dilated square A'B'C'D'
To find the coordinates of the vertices of dilated square, we need to multiply each vertices of ABCD by 3.
A(-1, -1) = 3(-1, -1) = A'(-3, -3)
B(1, -1) = 3(1, -1) = B'(3, -3)
C(1, 1) = 3(1, 1) = C'(3, 3)
D(-1, 1) = 3(-1, 1) = D'(-3, 3)
To find the area of the small square
the side of the small square is 2 units
so the are of the small square is = 4 square units
To find the area of the larger square
lets find the side AB of the square using distance formula
=>
=>
=>
=>
=>
=>6
AB =6 units
In a square all the sides will be equal
Now the area of the larger square will be
36 square units
The ratio of larger square to smaller square is
=>36 : 4
=>9 : 1
Answer:
A) Distance time graph
B) d(t) = 25t
C) The expression shows the distance more clearly.
Step-by-step explanation:
A) A distance time graph as seen in the attachment provides a representation of the distance travelled.
We are told the car travels at a constant speed of 100 meters per 4 seconds. Which means that 100 m for each 4 hours. So, for 200m, it's 8 hours like seen in the graph and for 300m,it's 12 hours as seen in the graph.
B) And expression for the distance is;
d = vt
Where;
d is distance in metres
v is speed in m/s and t is time
We are told that the car travels at a constant speed of 100 meters per 4 seconds.
Thus, v = 100/4 = 25 m/s
Distance travelled over time is;
d(t) = 25t
C) Looking at both A and B above, it's obvious that the expression of the distance shows a more clearer way of getting the distance because once we know the time travelled, we will just plug it into the equation and get the distance. Whereas, for the representation form, one will need to longer graphs if the time spent is very long.
