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3 years ago

I need to know ASAP what’s the missing number?

Mathematics

2 answers:

Goryan [66]3 years ago

5 0

Answer:

Step-by-step explanation:

ratio between all other pairs can be simplified to 2:11 if you divide each number by 2, 3, and 4 respectively

Rashid [163]3 years ago

4 0

The answer is 11 have a good day

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For the order of operations, Group of answer choices Multiplication, division and remainder is performed first Addition and subt

Furkat [3]

Answer: Addition and subtraction is performed after multiplication, division and remainder

Step-by-step explanation:

The correct order of operations is to calculate whatever is in the parenthesis first.

Then calculate multiplication and division depending on which comes first as you move from left to right.

Then addition and subtraction can be performed also depending on which comes first as you move left to right.

8 0

3 years ago

What is the correct factorization of х2 + 5х – 6?

nordsb [41]

The answer to your question is (x+6)(x-1)

6 0

3 years ago

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The price of gourmet coffee beans at the corner market has increased 10% per year over the past several years if the current cos

Anarel [89]

$20 because 10% of 40 is 10 and the price now is 40 so 2 years before would have been 20

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4 years ago

Read 2 more answers

Please help me! Find the number x such that f(x) =1

STatiana [176]

Answer:

Step-by-step explanation:

We have the piecewise function:

$f(x) = \left\{ \begin{array}{ll} -\frac{1}{2}x-1 & \quad x \leq -2 \\ x & \quad x > -2 \end{array} \right.$

And we want to find x such that f(x)=1.

So, let's substitute 1 for f(x):

$1 = \left\{ \begin{array}{ll} -\frac{1}{2}x-1 & \quad x \leq -2 \\ x & \quad x > -2 \end{array} \right.$

This has two equations. So, we can separate them into two separate cases. Namely:

$1=-\frac{1}{2}x-1\text{ or } 1=x$

Let's solve for x in each case.

Case I:

We have:

$1=-\frac{1}{2}x-1$

Add 1 to both sides:

$2=-\frac{1}{2}x$

Let's cancel out the fraction by multiplying both sides by -2. So:

$2(-2)=(-2)\frac{-1}{2}x$

The right side cancels:

$-4=x\\$

Flip:

$x=-4$

So, x is -4.

Case II:

We have:

$1=x$

Flip:

$x=1$

This is the solution for our second case.

So, we have:

$x_1=-4\text{ or } x_2=1$

Now, can check to see if we have to to remove solution(s) that don't work.

Note that x=-4 is the solution to our first equation.

The first equation is defined only if x is less than -2.

-4 is less than -2. So, x=-4 is indeed a solution.

x=1 is the solution to our second equation.

The second equation is defined only if x is greater than or equal to -2.

1 is greater than or equal to -2. So, x=1 is also a solution.

Therefore, our two solutions are:

$x_1=-4\text{ or } x_2=1$

Out of our answer choices, we can pick D.

And we're done!

7 0

4 years ago

You are riding the bus to school and you realize it is taking longer because of all the stops you are making. The time it takes

Ksju [112]

Answer:

-1

Step-by-step explanation:

g(2) = (2) - 3(2) + 4(2) - 5

g(2) = 2 - 6 + 8 - 5

g(2) = 2 - 6 + 3

g(2) = 2 - 3

g(2) = -1

4 0

3 years ago