<span>1.16 moles/liter
The equation for freezing point depression in an ideal solution is
ΔTF = KF * b * i
where
ΔTF = depression in freezing point, defined as TF (pure) ⒠TF (solution). So in this case ΔTF = 2.15
KF = cryoscopic constant of the solvent (given as 1.86 âc/m)
b = molality of solute
i = van 't Hoff factor (number of ions of solute produced per molecule of solute). For glucose, that will be 1.
Solving for b, we get
ΔTF = KF * b * i
ΔTF/KF = b * i
ΔTF/(KF*i) = b
And substuting known values.
ΔTF/(KF*i) = b
2.15âc/(1.86âc/m * 1) = b
2.15/(1.86 1/m) = b
1.155913978 m = b
So the molarity of the solution is 1.16 moles/liter to 3 significant figures.</span>
Answer:
C. Atom 3
Explanation:
I'm sorry if I answered this late, but hope this helps! :D
Molal concentration gives the number of moles dissolved in 1 kg of solution.
Molal concentration of H₂SO₄ is 2.88 mol/kg
the weight of H₂SO₄ in 1 kg - 2.88 mol x 98 g/mol = 282.2 g
The total weight of solution - 1000 g + 282.2 g = 1282.2 g
density of solution is 1.167 g/ml
We need to find how many moles are dissolved in 1 L.
We know the weight of the solution, using this we can calculate volume of the solution
volume of solution is - 1282.2 g / 1.167 g/mL = 1098.7 mL
The number of H₂SO₄ moles in 1.0987 L = 2.88 mol
Therefore in 1 L = 2.88 mol / 1.0987 L = 2.62 mol
Molarity of H₂SO₄ is 2.62 mol/L = 2.62 M
Answer:
(A) A layer of gases that surrounds the planet
Explanation:
An atmosphere is the layer of gases that surrounds a planet. In the case of Earth, the atmosphere contains the air we breath, as well as other gases that protect us from the Sun's harmful rays.
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