Answer:
The middle ear is the portion of the ear internal to the eardrum, and external to the oval window of the inner ear. The mammalian middle ear contains three ossicles, which transfer the vibrations of the eardrum into waves in the fluid and membranes of the inner ear.
Explanation:
Answer:
24.6 atm
Explanation:
Step 1: Given and required data
- Pressure of carbon dioxide (P): ?
- Volume of carbon dioxide (V): 1.00 L
- Moles of carbon dioxide (n): 1.00 mol
- Ideal gas constant (R): 0.08206 atm.L/mol.K
- Temperature of carbon dioxide (T): 300 K
Step 2: Calculate the pressure of carbon dioxide
Assuming ideal gas behavior, we will use the ideal gas equation.
P × V = n × R × T
P = n × R × T/V
P = 1.00 mol × 0.08206 atm.L/mol.K × 300 K/1.00 L
P = 24.6 atm
Answer:
Physical change is the change that you can see like for example if you turn your light on and off thats physical (thats the best definition for that i can do) and also physical change can go back to its original form it was before. A chemical change is when you do something to something and it cannot be changed back to its original form. Like for example, if you bake a pie, you cannot un-cook all the ingredients to make it raw again
Explanation:
learned this in 5th grade
Answer:
The curve is still exponential but decreases at a lower rate for a greater half-life;
The greater the half-life, the slower radioactive decay is.
Explanation:
From the context of the actual problem, it looks like you plotted the number of non-decayed atoms against time. Since you are analyzing a radioactive decay in this problem, the number of the atoms remaining for the first-order rate law can be represented by the following equation:
Here k is the rate constant. It is defined in terms of half-life by the following relationship:
That said, in terms of half-life, our equation becomes:
Notice that the greater the half-life is, the less negative the coefficient in front of the time variable in the exponent.
As a result, the decay for a greater half-life would occur at a lower rate. The curve would still be exponential in terms of shape but would decrease at a lower rate.
We may conclude that the greater the half-life, the slower radioactive decay is.