<u>larger is the value of </u>
<u> the higher will the solubility of solid in water.</u>
What is called compound?
- In chemistry, a compound is a substance made up of two or more different chemical elements combined in a fixed ratio.
- When the elements come together, they react with each other and form chemical bonds that are difficult to break.
- These bonds form as a result of sharing or exchanging electrons between atoms.
The equation for the dissociation of a solid MX in water is given below
MX(s) ⇄ Mⁿ⁺(aq) + Xⁿ⁻ (aq)
Assume s be the solubility of MX in pure water, then the equilibrium concentrations of ions are
[ Mⁿ⁺] = s
[ Xⁿ⁻ ] = s
The expression for the solubility product constant () is as follows
= [ Mⁿ⁺] [ Xⁿ⁻ ]
= s²
That is, larger is the value of the higher will the solubility of solid in water.
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It will form mountains, hope this helps
Answer:
Option C. 4.03 g
Explanation:
Firstly we analyse data.
12 % by mass, is a sort of concentration. It indicates that in 100 g of SOLUTION, we have 12 g of SOLUTE.
Density is the data that indicates grams of solution in volume of solution.
We need to determine, the volume of solution for the concentration
Density = mass / volume
1.05 g/mL = 100 g / volume
Volume = 100 g / 1.05 g/mL → 95.24 mL
Therefore our 12 g of solute are contained in 95.24 mL
Let's finish this by a rule of three.
95.24 mL contain 12 g of sucrose
Our sample of 32 mL may contain ( 32 . 12) / 95.24 = 4.03 g
Answer : The reagent present in excess and remains unreacted is, 
Solution : Given,
Moles of 
= 3.00 mole
Moles of = 2.00 mole
Excess reagent : It is defined as the reactants not completely used up in the reaction.
Limiting reagent : It is defined as the reactants completely used up in the reaction.
Now we have to calculate the limiting and excess reagent.
The balanced chemical reaction is,
From the balanced reaction we conclude that
As, 2 moles of react with 1 mole of
So, 3.00 moles of react with 
moles of
From this we conclude that, is an excess reagent because the given moles are greater than the required moles and is a limiting reagent and it limits the formation of product.
Hence, the reagent present in excess and remains unreacted is,
Aluminum is 26.982 grams per mole, so 26.982/19.9 will give you the moles 1.3558794
