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masha68 [24]
3 years ago
15

Consider the reaction: CaCO3(s) à CaO(s) + CO2(g)

Chemistry
1 answer:
Vsevolod [243]3 years ago
6 0

Answer:

131.5 kJ

Explanation:

Let's consider the following reaction.

CaCO₃(s) → CaO(s) + CO₂(g)

First, we will calculate the standard enthalpy of the reaction (ΔH°).

ΔH° = 1 mol × ΔH°f(CaO(s)) + 1 mol × ΔH°f(CO₂(g) ) - 1 mol × ΔH°f(CaCO₃(s) )

ΔH° = 1 mol × (-634.9 kJ/mol) + 1 mol × (-393.5 kJ/mol) - 1 mol × (-1207.6 kJ/mol)

ΔH° = 179.2 kJ

Then, we calculate the standard entropy of the reaction (ΔS°).

ΔS° = 1 mol × S°(CaO(s)) + 1 mol × S°(CO₂(g) ) - 1 mol × S°(CaCO₃(s) )

ΔS° = 1 mol × (38.1 J/mol.K) + 1 mol × (213.8 J/mol.K) - 1 mol × (91.7 J/mol.K)

ΔS° = 160.2 J/K = 0.1602 kJ/K

Finally, we calculate the standard Gibbs free energy of the reaction at T = 25°C = 298 K.

ΔG° = ΔH° - T × ΔS°

ΔG° = 179.2 kJ - 298 K × 0.1602 kJ/K

ΔG° = 131.5 kJ

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With white light, a team measured a 0.7% percent change with 3.5g of plant matter in a one liter container. Convert
Strike441 [17]

moles CO₂ = 5.57.10⁻⁴

<h3>Further explanation   </h3>

A mole is a number of particles(atoms, molecules, ions)  in a substance

Can be formulated :

\tt mol=\dfrac{mass}{MW}

0.7% percent change with 3.5g of plant matter

mass :

\tt 0.7\%\times 3.5~g=0.0245~g

moles :

\tt moles=\dfrac{0.0245}{44}=0.000557=5.57.10^{-4}

5 0
3 years ago
Cavendish’s name for hydrogen gas was "inflammable air." The word inflammable means "to burn. "Why did Cavendish use this name?
saul85 [17]
He used that name because if you lit hydrogen on fire it would catch. therefore, it was dangerous to be around. think of it as a kind of warning. :) hope that helps.
8 0
3 years ago
Read 2 more answers
I need help pls, and fast.
Vadim26 [7]

Answer:

1) Liquid forms drops that are dome-shaped

2) low surface tension

3) low viscosity

4) Liquid is thick and pours very slowly

Explanation:

It makes sense just use the stuff that's already in the table. It usually works.

7 0
3 years ago
1) A mixture of anhydrous sodium carbonate and sodium hydrogencarbonate of mass 10.000 g was heated until it reached a constant
vodomira [7]

The masses of the components are obtained as;

  • Sodium hydrogen carbonate = 3.51 g
  • Sodium carbonate =  8.708 g
<h3>What is decomposition?</h3>

The term decomposition has to do with the breakdown of the given substance into its components. The components of sodium hydrogen carbonate could be identified as water vapor, carbon dioxide gas and sodium carbonate. Among these products that have been listed here, we can see that it is only the sodium carbonate that remains as a solid. The others are gases that move away from the system that is under study.

Now putting down the equation of the reaction, we have;

2NaHCO_{3} (s) ----- > Na_{2} CO_{3} (s) + CO_{2} (g) + H_{2} O(g)

Now, the loss in  mass must be due to the carbon dioxide and the water. Hence we obtain the loss in mass to be 10.000 g -  8.708 g = 1.292 g

Mass of sodium hydrogen carbonate = 2 * 88 g/mol * 1.292 g/62 g/mol

= 3.51 g

Learn more about anhydrous sodium carbonate :brainly.com/question/20479996

#SPJ1

6 0
1 year ago
Naoki's bicycle has a mass of 10 kg. If Naoki sits on her bicycle and starts pedaling with a force of 168 N, causing an accelera
White raven [17]

Answer:

50 kg

Explanation:

Data:

Mass of bicycle = 10 kg

                       F = 168 N

                       a = 2.8 m/s²

Calculation:

                     F = ma     Divide each side by m, Then

                 m = F/a

                     = 168/2.8

                      = 60 kg

                 m = mass of bicycle + Naoki's mass. Then

                60 = 10 + Naoki's mass     Subtract 10 from each side

Naoki's mass = 50 kg

3 0
3 years ago
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