1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Oksanka [162]
3 years ago
7

How many moles of oxygen (O) atoms are in a sample of 3.98 × 1023 atoms? 0.661 mol O 1.51 mol O 6.60 × 1022 mol O 2.40 × 1047 mo

l O
Chemistry
1 answer:
lidiya [134]3 years ago
7 0
To find moles from any number of atoms, always divide by the constant called Avogadro's Number. This number is representative of the number of atoms or molecules in a mole of any substance and is equal to about 6.022* 10^{23} 
.

So, for this problem, we take the number of atoms of oxygen and divide by Avogadro's Number. 

\frac{3.98*  10^{23}  O_{2} atoms  }{6.022*  10^{23} atoms/mol  } = 0.6609 moles

Answer: 0.661 moles (after rounding)

Make sense?
You might be interested in
John roller skates 48 km in 3 hours. What is his average speed in kilometers
Nadya [2.5K]

Answer:16km/hr

Explanation:

48km/3hr= 16km/hr

7 0
3 years ago
Read 2 more answers
The product of adding two molecules of an alcohol to an aldehyde in the presence of acid is a(n):______
Anna35 [415]

Answer:

A

Explanation:

Acetals are geminal-diether derivatives of aldehydes or ketones, formed by reaction with two equivalents (or an excess amount) of an alcohol and elimination of water. Ketone derivatives of this kind were once called ketals, but modern usage has dropped that term.

To achieve effective hemiacetal or acetal formation, two additional features must be implemented. First, an acid catalyst must be used because alcohol is a weak nucleophile and second the water produced with the acetal must be removed from the reaction.

3 0
4 years ago
Read 2 more answers
If a 3.0 picogram (pg) sample of curium-245 has a half-life of 8500 years, which conclusion can be drawn?
fomenos

Answer:

its A

Explanation:

8 0
3 years ago
Name 3 common accelerants used in arson
Makovka662 [10]

Answer:

Common ones are Gasoline, Diesel fuel, and Kerosene.

Explanation:

Many accelerants are hydrocarbon-based fuels, sometimes referred to as petroleum distillates: gasoline, diesel fuel, kerosene, turpentine, butane, and various other flammable solvents. These accelerants are also known as ignitable liquids. Ignitable liquids can leave behind tell-tale marks in the fire debris.

Hoped this had helped you :)

7 0
3 years ago
What molecules are involved in transcription?
Mars2501 [29]
Enzymes Transcription: Transcription factors (eukaryotes), RNA polymerase 
<span>Enzymes Translation: initiation factors, elongation factors, termination factors </span>
<span>Molecules transcription: mRNA , DNA </span>
<span>Molecules translation: ribosomes, tRNA, mRNA, GTP (energy source)</span>
8 0
3 years ago
Read 2 more answers
Other questions:
  • If you go into the lab and dissolve 2.11 g of magnesium chloride in enough water to make 1500 ml of solution, what is the molari
    12·1 answer
  • Why is the sky orange and red at sunrise and sunset?
    6·1 answer
  • A tank contains 9000 L of pure water. Brine that contains 20 g of salt per liter of water is pumped into the tank at a rate of 2
    5·1 answer
  • Is heavenly controller dating someone?
    9·1 answer
  • Electric charge<br> A. discovery b. Radiation c.electricity d. Kinetic energy
    6·1 answer
  • Balance Fe3O4 + H2 = Fe + H2O
    14·1 answer
  • How many grams are in 2.0 × 1024 atoms of C?
    5·1 answer
  • The average temperature of healthy person is 98.6°F. What is it in<br> Celsius scale?
    8·1 answer
  • If you attempt to produce work using the formation reaction of methanol (CH3OH), and the reaction is carried out reversibly, wha
    6·1 answer
  • How many grams of solute would you use to prepare the following solutions?241.0 mL of 1.11 M NaOHExpress your answer with the ap
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!