Answer:
1,712,304 ways
Step-by-step explanation:
This problem bothers on combination
Since we are to select 5 subjects from a pool of 48 subjects, the number of ways this can be done is expressed as;
48C5 = 48!/(48-5)!5!
48C5 = 48!/43!5!
48C5 = 48×47×46×45×44×43!/43!5!
48C5 = 48×47×46×45×44/5!
48C5 = 205,476,480/120
48C5 = 1,712,304
Hence this can be done in 1,712,304ways
$24 because $192divided by $8 is $24
3+4x=15
4x=15-3
4x=12
x=12/4
x=3
The check is:
<span>If x=3 then, </span>
3+ (4 X 3)=15
<span>3+12=15</span>
Answer:
47
Step-by-step explanation:
Let a, b, and c be those three numbers.
When two of the three numbers are added at a time, the possible sums are 32, 39, 23. Let
Add these three equations:
Divide this equation by 2:
The sum of all three numbers is 47.
Answer:
ill take those points rq
Step-by-step explanation:
