Answer:
The area of triangle K is 16 times greater than the area of triangle J
Step-by-step explanation:
we know that
If Triangle K is a scaled version of Triangle J
then
Triangle K and Triangle J are similar
If two triangles are similar, then the ratio of its areas is equal to the scale factor squared
Let
z -----> the scale factor
Ak ------> the area of triangle K
Aj -----> the area of triangle J
so

we have

substitute



therefore
The area of triangle K is 16 times greater than the area of triangle J
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Answer:
Step-by-step explanation:
1+2
+2v+4
Step-by-step explanation:
sorry for the rough handwriting but that's that
Answer:
Angle 1 = 39, Angle 2 = 78 , Angle 3 = 63
Step-by-step explanation:
78/2 = 39
(Angle 2/2 = Angle 1)
78 - 15 = 63
(Angle 2 - 15 = Angle 3)
39 + 78 + 63 = 180
(Angle 1 + Angle 2 + Angle 3 = 180)