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Mekhanik [1.2K]
3 years ago
6

On a temperature versus time graph, how does the temperature at the beginning of a change of state compare with the temperature

at the end of the change?

Chemistry
2 answers:
algol [13]3 years ago
5 0

Answer:

It Remains Constant

Explanation:

When the temperature over a matter remains constant, subsequently the kinetic energy among them is also constant, then there is a phase change.

The graph is a linear function given by the formula, which measures the heat necessary in the system:

Q=mcΔt

So it increases linearly in the same state. Remains constant when there's a change of state. According to the function above and the graph below.

Dominik [7]3 years ago
3 0

<span>In a temperature time graph, the change of state at beginning is increasing rapidly like a exponential function. This is due to the fact that at the beginning the difference in temperature is much greater so the driving force is great. Towards the end the change is already very minimal or none because the difference is now almost zero</span>

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Aquafers are bodies of water found above ground with thriving ecosystems.<br> O True<br> O False
BaLLatris [955]

Answer:

true

Explanation:

8 0
3 years ago
What four things affect the tides
S_A_V [24]
I know three
The Moon
The Wind
and Earths Rotation.

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3 years ago
The percent by mass of bicarbonate (HCO3−) in a certain Alka-Seltzer product is 32.5 percent. Calculate the volume of CO2 genera
nevsk [136]

Answer:

The volume of carbon dioxide gas generated 468 mL.

Explanation:

The percent by mass of bicarbonate in a certain Alka-Seltzer = 32.5%

Mass of tablet = 3.45 g

Mass of bicarbonate =3.45 g\times \frac{32.5}{100}=1.121 mol

Moles of bicarbonate ion = \frac{1.121 g/mol}{61 g/mol}=0.01840 mol

HCO_3^{-}(aq)+HCl(aq)\rightarrow H_2O(l)+CO_2(g)+Cl^-(aq)

According to reaction, 1 mole of bicarbonate ion gives with 1 mole of carbon dioxide gas , then 0.01840 mole of bicarbonate ion will give:

\frac{1}{1}\times 0.01840 mol=0.01840 mol of carbon dioxide gas

Moles of carbon dioxide gas  n = 0.01840 mol

Pressure of the carbon dioxide gas = P = 1.00 atm

Temperature of the carbon dioxide gas = T = 37°C = 37+273 K=310 K

Volume of the carbon dioxide gas = V

PV=nRT (ideal gas equation)

V=\frac{nRT}{P}=\frac{0.01840 mol\times 0.0821 atm L/mol K\times 310 K}{1.00 atm}=0.468 L

1 L = 1000 mL

0.468 L =0.468 × 1000 mL = 468 mL

The volume of carbon dioxide gas generated 468 mL.

5 0
3 years ago
A solution contains 0.140 mol KCl in 2.100 L water. What is the concentration of KCl in g/L?
viva [34]
<h3><u>Answer</u>;</h3>

≈ 4.95 g/L

<h3><u>Explanation;</u></h3>

The molar mass of KCl = 74.5 g/mole

Therefore; 0.140 moles will be equivalent to ;

 = 0.140 moles × 74.5 g/mole

 = 10.43 g

Concentration in g/L

   = mass in g/volume in L

   = 10.43/2.1

   =  4.9667

<h3>   <u> ≈ 4.95 g/L</u></h3>
4 0
3 years ago
The amount of fat recommended for somone with a daily diet of 2000 Calories is 65 g. What percent of the calories in this diet w
Doss [256]

Answer:

29.575%

Explanation:

Data provided:

Calories taken in daily diet = 2000

Recommended amount of fat = 65 grams

Average number of calories for fat = 9.1 calories / g

Thus,

Number of calories in the diet with average number of calories for fat

= Recommended amount of fat × Average number of calories for fat

= 65 × 9.1

= 591.5 calories

Therefore,

the percentage of calories in his diet supplied = ( 591.5 / 2000 ) × 100

= 29.575%

6 0
3 years ago
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