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Mekhanik [1.2K]
4 years ago
6

On a temperature versus time graph, how does the temperature at the beginning of a change of state compare with the temperature

at the end of the change?

Chemistry
2 answers:
algol [13]4 years ago
5 0

Answer:

It Remains Constant

Explanation:

When the temperature over a matter remains constant, subsequently the kinetic energy among them is also constant, then there is a phase change.

The graph is a linear function given by the formula, which measures the heat necessary in the system:

Q=mcΔt

So it increases linearly in the same state. Remains constant when there's a change of state. According to the function above and the graph below.

Dominik [7]4 years ago
3 0

<span>In a temperature time graph, the change of state at beginning is increasing rapidly like a exponential function. This is due to the fact that at the beginning the difference in temperature is much greater so the driving force is great. Towards the end the change is already very minimal or none because the difference is now almost zero</span>

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Here is the electron configuration for Magnesium. How many total electrons are in the 2nd energy level?
balandron [24]

Answer:

8 electrons

Explanation:

Magnesium is present on group 2.

It has 2 valence electrons.

Electronic configuration of magnesium:

Mg₁₂ = 1s² 2s² 2p⁶ 3s²

1st energy level contain 2 electrons.(1s²)

2nd energy  level contain 8 electrons. (2s² 2p⁶)

3rd energy level contain 2 electrons. (3s²)

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How long do fresh cranberries last in the refrigerator?
vodka [1.7K]

Answer:

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7 0
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3 years ago
An industrial process of producing ammonia gas runs with a 74.0% yield. How many kilograms of ammonia gas will be produced in th
Tcecarenko [31]

Answer:

37.1 kilograms of ammonia gas will be produced in this process

Explanation:

The percentage yield of the reaction is given by:

(Yield)\%=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

According to question

The percentage yield of the given industrial process = 74.0%

The given theoretical yield of ammonia gas = 50.1 kg

The experimental yield of ammonia gas = x

The percentage yield of the reaction is calculated a:

74.0\%=\frac{x}{50.1 kg}\times 100

Solving for x, we get:

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37.1 kilograms of ammonia gas will be produced in this process

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