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3 years ago

A fault cuts across several layers of rock. Which conclusion can be made?(1 point)

Chemistry

1 answer:

xxTIMURxx [149]3 years ago

7 0

Answer: The fault is younger than the layers of rock, according to the law of crosscutting.

Explanation:

Then Law of Crosscutting which was described by James Hutton explains that whenever a fault is seen on a rock, the fault will always be younger than the rock it is one.

This makes sense because if there was no rock in the first place, the fault would not have cut through it. But because there was a rock and an object exacted a force in order to move through the rock, the fault appeared showing that the rock came first, then came the fault.

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Question 1 1 pts How many mols of bromine are present in 35.7g of Tin(IV) bromate?

sleet_krkn [62]

Answer:

n = 0.0814 mol

Explanation:

Given mass, m = 35.7g

The molar mass of Tin(IV) bromate, M = 438.33 g/mol

We need to find the number of moles of bromine. We know that,

No. of moles = given mass/molar mass

So,

$n=\dfrac{35.7}{438.33}\\\\n=0.0814\ mol$

So, there are 0.0814 moles of bromine in 35.7g of Tin(IV) bromate.

3 0

3 years ago

50 Points: What is the mass of 6.12 moles of arsenic (As)?

ozzi

The mass of 6.12 moles of arsenic (As) is calculated to be approximately 459g.

HOW TO CALCULATE MASS:

The mass of a substance can be calculated by multiplying the number of moles of a substance by its molar mass. That is;

Mass of Arsenic = no. of moles of As × molar mass of As.

According to this question, 6.12 moles of arsenic was given and its molar mass is 74.92g/mol.

Mass of As = 6.12 mol × 74.92g/mol

Mass of As = 459g

Therefore, the mass of 6.12 moles of arsenic (As) is calculated to be approximately 459g.

Learn more about mass calculations at: brainly.com/question/8101390

4 0

3 years ago

At a certain temperature and pressure, 0.20 mol of carbon dioxide has a volume of 3.1 L. A 3.1-L sample of hydrogen at the same

Arada [10]

A 3.1 L sample of hydrogen d. contains the same number of molecules

as 3.1 L of carbon dioxide at the same temperature and pressure.

This is the fundamental principle of Avogadro’s hypothesis: equal volume of gases at the same temperature and pressure contain the same number of molecules.

The sample of carbon dioxide has a greater mass, a greater number of atoms, and a greater density, than the sample of hydrogen.

7 0

3 years ago

HELP PLEASEE ITS ALREADY PAST DUE I NEED THIS

FromTheMoon [43]

i think its b because yeah

5 0

3 years ago

Read 2 more answers

At 850°C, CaCO3 undergoes substantial decomposition to yield CaO and CO2. Assuming that the ΔH o f values of the reactant and pr

Xelga [282]

Answer:

The enthalpy if 68.10 grams of CO2 is produced is -189.04 kJ

Explanation:

Step 1: Data given

temperature = 850 °C

Mass of 68.10 grams of CO2

ΔH°f (CaO) = -635.6 kJ/mol

ΔH°f (CO2) = -693.5 kJ/mol

ΔH°f (CaCO3) =-1206.9 kJ/mol

Step 2: The balanced equation

CaCO3(s) → CaO(s) + CO2(g)

Step 3: Calculate ΔH°reaction

ΔH°reaction = ΣΔH°f (products) - ΣΔH°f (reactants)

ΔH°reaction = (ΔH°f (CaO) + ΔH°f (CO2)) - ΔH°f (CaCO3)

ΔH°reaction = (-635.6 kJ/mol + -693.5 kJ/mol) + 1206.9 kJ/mol

ΔH°reaction = -122.2 kJ /mol

Step 4: Calculate moles of CO2

Moles CO2 = mass CO2 / Molar mass CO2

Moles CO2 = 68.10 grams / 44.01 g/mol

Moles CO2 = 1.547 moles

Step 5: Calculate the enthalpy change for 68.10 grams of CO2

-122.2 kJ/mol * 1.547 moles = -189.04 kJ

The enthalpy if 68.10 grams of CO2 is produced is -189.04 kJ

7 0

3 years ago