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3 years ago

7

A fault cuts across several layers of rock. Which conclusion can be made?(1 point)

1 answer:

xxTIMURxx [149]3 years ago

7 0

Answer: The fault is younger than the layers of rock, according to the law of crosscutting.

Explanation:

Then Law of Crosscutting which was described by James Hutton explains that whenever a fault is seen on a rock, the fault will always be younger than the rock it is one.

This makes sense because if there was no rock in the first place, the fault would not have cut through it. But because there was a rock and an object exacted a force in order to move through the rock, the fault appeared showing that the rock came first, then came the fault.

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The combustion of 1.5011.501 g of fructose, C6H12O6(s)C6H12O6(s) , in a bomb calorimeter with a heat capacity of 5.205.20 kJ/°C

avanturin [10]

Answer : The internal energy change is -2805.8 kJ/mol

Explanation :

First we have to calculate the heat gained by the calorimeter.

$q=c\times (T_{final}-T_{initial})$

where,

q = heat gained = ?

c = specific heat = $5.20kJ/^oC$

$T_{final}$ = final temperature = $27.43^oC$

$T_{initial}$ = initial temperature = $22.93^oC$

Now put all the given values in the above formula, we get:

$q=5.20kJ/^oC\times (27.43-22.93)^oC$

$q=23.4kJ$

Now we have to calculate the enthalpy change during the reaction.

$\Delta H=-\frac{q}{n}$

where,

$\Delta H$ = enthalpy change = ?

q = heat gained = 23.4 kJ

n = number of moles fructose = $\frac{\text{Mass of fructose}}{\text{Molar mass of fructose}}=\frac{1.501g}{180g/mol}=0.00834mole$

$\Delta H=-\frac{23.4kJ}{0.00834mole}=-2805.8kJ/mole$

Therefore, the enthalpy change during the reaction is -2805.8 kJ/mole

Now we have to calculate the internal energy change for the combustion of 1.501 g of fructose.

Formula used :

$\Delta H=\Delta U+\Delta n_gRT$

or,

$\Delta U=\Delta H-\Delta n_gRT$

where,

$\Delta H$ = change in enthalpy = $-2805.8kJ/mol$

$\Delta U$ = change in internal energy = ?

$\Delta n_g$ = change in moles = 0 (from the reaction)

R = gas constant = 8.314 J/mol.K

T = temperature = $27.43^oC=273+27.43=300.43K$

Now put all the given values in the above formula, we get:

$\Delta U=\Delta H-\Delta n_gRT$

$\Delta U=(-2805.8kJ/mol)-[0mol\times 8.314J/mol.K\times 300.43K$

$\Delta U=-2805.8kJ/mol-0$

$\Delta U=-2805.8kJ/mol$

Therefore, the internal energy change is -2805.8 kJ/mol

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3 years ago

Which of these phenomena cause uneven heating of the earth

Ostrovityanka [42]

Answer:

The angle of incoming sunlight varies at different places

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Miles and pounds are use in which systems?

lisabon 2012 [21]

Answer:

The United States customary system aka USCS or USC?

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Colligative properties are dependent only on the number of particles in a solution, and not their identity. (select all that app

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The answer will be apart of a 60 caculace so it will equal to a efficacy amount so d

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2 years ago

If an element has 12 protons, 13 neutrons, and 15 electrons, what is its mass?

-BARSIC- [3]

Answer:

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Explanation:

mass number = protons + neutrons

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