Answer:
The solution and complete explanation for the above question and mentioned conditions is given below in the attached document.i hope my explanation will help you in understanding this particular question.
Explanation:
Answer:
water rise = 22 mm
Explanation:
weight of packet IN AIR = 40 *9.81 =392.4 N
weight of packet IN WATER= 18 *9.81 =176.58 N
by Archimedi's principle
difference in weight = weight of displaced water
w_a - w_w = \rho_w v_d g
392.4 - 176.58 = 1000* v_d* 9.81
v_d = 0.022 m^3
v_d = A*H_rise
0.022 =1*H_rise
H_rise = 0.022 m = 22 mm
water rise = 22 mm
Answer:
If analyzed by volume capacity, more trips are needed to fill the space, thus the required trips are 288
Explanation:
a) By volume.
The shrinkage factor is:
The volume at loose is:
If the Herrywampus has a capacity of 30 cubic yard:
b) By weight
The swell factor in terms of percent swell is equal to:
The weight of backfill is:
The Herrywampus has a capacity of 40 ton:
If analyzed by volume capacity, more trips are needed to fill the space, thus the required trips are 288
Answer:
The final temperature in the vessel after the resistor has been operating for 30 min is 111.67°C
Explanation:
given information:
mass, m = 3 kg
initial temperature, T₁ = 40°C
current, I = 10 A
voltage, V = 50 V
time, t = 30 min = 1800 s
Heat for the system because of the resistance is
Q = V I t
where
V = voltage (V)
I = current (A)
t = time (s)
Q = heat transfer to the system (J)
so,
Q = V x I x t
= 50 x 10 x 1800
= 900000
= 9 x 10⁵ J
the heat transfer in the closed system is
Q = ΔU + W
where
U = internal energy
W = work done by the system
thus,
Q = ΔU + W
9 x 10⁵ = ΔU + 0, W = 0 because the tank is a well-insulated and rigid.
ΔU = 9 x 10⁵ J = 900 kJ
then, the energy change in the system is
ΔU = m c ΔT
ΔT = ΔU / m c, c = 4.186 J/g°C
= 900 / (3 x 4.186)
= 71.67°C
so,the final temperature (T₂)
ΔT = T₂ - T₁
T₂ = ΔT + T₁
= 71.67°C + 40°C
= 111.67°C
