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Nataliya [291]
3 years ago
8

At what temperature does 0.019135 moles of Ne in a 878.3 mL container exert a pressure of 0.946 atm?

Chemistry
2 answers:
azamat3 years ago
7 0

Temperature of gas Ne : <u>529.208 K</u>

<h3>Further explanation  </h3>

Some of the laws regarding gas, can apply to ideal gas (volume expansion does not occur when the gas is heated), among others  

  • Boyle's law at constant T, P = 1 / V  
  • Charles's law, at constant P, V = T  
  • Avogadro's law, at constant P and T, V = n  

So that the three laws can be combined into a single gas equation, the ideal gas equation  

In general, the gas equation can be written  

\large{\boxed{\bold{PV=nRT}}}  

where  

P = pressure, atm  

V = volume, liter  

n = number of moles  

R = gas constant = 0.08205 l.atm / mol K  

T = temperature, Kelvin  

Gas Ne with :

moles : 0.019135

volume : 878.3 ml = 0.8783 L

Pressure : 0.946 atm

Plug in gas ideal equation :

\rm T=\dfrac{PV}{nR}\\\\T=\dfrac{0.946\times 0.8783}{0.019135\times 0.08205}\\\\T=\boxed{\bold{529.208\:K}}

<h3>Learn more  </h3>

Which equation agrees with the ideal gas law  

brainly.com/question/3778152  

brainly.com/question/1056445  

Which law relates to the ideal gas law  

brainly.com/question/6534096  

Reika [66]3 years ago
5 0
<h3>Answer:</h3>

Temperature is 529.164 K

<h3>Explanation:</h3>

We are given

Number of moles of Ne (n) =  0.019135 moles

Volume (V) = 878.3 mL

Pressure (P) = 0.946 atm

We are required to calculate the temperature;

We can do this using the ideal gas law equation which is;

PV = nRT, where P is the pressure, n is the number of moles, V is the volume, R is the ideal gas constant (0.082057 Latm/mol/K) and T is the temperature.

From the equation;

T=\frac{PV}{nR}

T = \frac{(0.946)(0.8783)}{(0.082057)(0.019135)}

T=529.164 K

Therefore, the temperature will be 529.164 K.

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