Answer:
Velocity of the ball after 3.04 (s) = 29.79 (m/s)
Explanation:
From the free fall movement we have the following formulas: and
, First we need to find the height to time iqual to 3.04 s using the formula:
and remember that golf ball was released from the rest (Vo= 0 (m/s)) so
, we get: h = -45.28 (m) with the height that we have got, now the velocity of the ball is calculate using
solving for Vf, we get:
replacing the values given
, so we get: Vf = 29.79 (m/s).
This question is incomplete the complete question is
A diver bounces straight up from a diving board, avoiding the diving board on the way down, and falls feet first into a pool. She starts with a velocity of 4.00 m/s and her takeoff point is 1.80 m above the pool. (a) What is her highest point above the board? (b) How long a time are her feet in the air? (c) What is her velocity when her feet hit the water?
Answer:
(a) Xs=0.459m
(b) t=0.984 s
(c) Vc=6.65 m/s
Explanation:
(a) To reach maximum distance
(b) For Time
To find t we must find t1 and t2
as
t=t1+t2
For T1
For T2
For Total Time
t=t1+t2
t=0.306+0.6789
t=0.984s
(c) To find Vc
Vc=Vb+gt2
Vc=(0)+(9.8)(0.6789)
Vc=6.65 m/s