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hodyreva [135]
4 years ago
12

A gas is contained in a horizontal cylinder with a moveable piston of cross-sectional area 0.33\text{ m}^20.33 m 2 . The region

outside the cylinder is at standard ambient temperature and pressure, 298\text{ K}298 K and 1\text{ bar}1 bar. When 2040\text{ J}2040 J of heat flow into the gas, the internal energy of the gas increases by 1380\text{ J}1380 J. Calculate the distance through which the piston moves. You may assume friction is negligible.
Chemistry
1 answer:
-BARSIC- [3]4 years ago
4 0

Answer:

0.02 m

Explanation:

∆U = q + w

w = ∆U - q = (1380 - 2040) J = -660 J

w = -p∆V = -pA∆h

∆h = -w/(pA)

p = 1 bar × (100000 Pa/1 bar) = 100000 Pa

∆h = -(-660 J)/(100000 Pa×0.33 m²) = 0.02 m

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