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Andru [333]
2 years ago
15

13. How many moles of sodium hydroxide are needed to neutralize 50grams of sulfuric acid?

Chemistry
1 answer:
Phoenix [80]2 years ago
6 0

Answer:

1.02mole

Explanation:

The reaction equation is given as:

     2NaOH  +  H₂SO₄ →  Na₂SO₄  + 2H₂O

Given:

Mass of H₂SO₄  = 50g

Unknown:

Number of moles of NaOH = ?

Solution:

To solve this problem, we first find the number of moles of the acid given;

  Number of moles  = \frac{mass}{molar mass}

Molar mass of H₂SO₄ = 2(1) + 32 + 4(16)  = 98g/mol

Now;

   Number of moles = \frac{50}{98}   = 0.51mole

From the balanced reaction equation:

       1 mole of H₂SO₄ will be neutralized by 2 mole of NaOH

     0.51 mole of H₂SO₄ will be neutralized by 2 x 0.51  = 1.02mole of NaOH

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<u>Answer:</u> The p-function of Zn^{2+} and NO_3^{-} ions are 2.51 and 2.14 respectively.

<u>Explanation:</u>

p-function is defined as the negative logarithm of any concentration.

We are given:

Millimolar concentration of zinc nitrate = 3.1 mM

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Converting this into molar concentration, we use the conversion factor:

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Putting values in above equation, we get:

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\text{p-function of }Zn^{2+}\text{ ions}=-\log[Zn^{2+}]

\text{p-function of }Zn^{2+}\text{ ions}=-\log(0.0031)\\\\\text{p-function of }Zn^{2+}\text{ ions}=2.51

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\text{p-function of }NO_3^{-}\text{ ions}=-\log[NO_3^{-}]

\text{p-function of }NO_3^{-}\text{ ions}=-\log(0.0073)\\\\\text{p-function of }NO_3^{-}\text{ ions}=2.14

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Explanation:

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