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Jet001 [13]
3 years ago
12

How many atoms are found in 12.0 grams of Helium?

Chemistry
2 answers:
Allisa [31]3 years ago
3 0
<span>Each mole contains Avagodro's number of atoms i.e. 6.023x10^23, so

3 moles x 6.023x10^23 atoms/mole = 18.069x10^23 atoms = 1.8x19^24 atoms </span>
Furkat [3]3 years ago
3 0
<span>One mole of helium has a mass of 4.0 grams. In 12 grams there are 3 moles of He. Each mole contains 6.022x10^23 atoms of helium. Therefore, 3 moles of He will contain 3 times as many atoms or 1.806x10^24 atoms.</span>
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According to the following reaction, how many grams of water are produced in the complete reaction of grams of sulfuric acid?
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This question requires the mass of sulfuric acid and a balance equation. The complete question is given below

Question:

According to the following reaction, how many grams of water are produced in the complete reaction of 24.1 grams of sulfuric acid?

H₂SO₄(aq) + Zn(OH)₂(s) ---------> ZnSO₄(aq) + 2H₂O(l)

Answer:

8.85 grams of water is obtained from 24.1 grams of sulfuric acid according to the given reaction

Explanation:

In this problem, the mass of water can be determined by using the balanced chemical equation.

Step 1: Write all data

Molar mass of water = 18 g

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Step 2: Write statement for conversion

Given equation shows that

1 mole of H₂SO₄ gives 2 moles of water

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