Explanation:
The O atom is sp3 in a water molecule, with two sigma bonds and two lone pairs of electrons like that in water. The steric integer is thus 4, and its structure is tetrahedral.
The C atom is sp hybridised into two identical bonds and two identical bonds in acetylene.
The steric integer is therefore 2 because only sigma bonds are engaged in deciding hybridization, and its structure is linear.
The C atom is sp2 hybridised in ethene with single pi bond and three sigma identical bonds.
Thus the steric integer is 3, and its structure is planar trigonal.
The C atom is sp2 hybridized in ethene, with one pi bond and three sigma identical bonds.
The steric integer would therefore be 3 and its structure is planar trigonal.
The O atom is sp3 in a water molecule with two bond pairs and two lone pairs of electrons like that. The steric integer is thus 4, and its structure is tetrahedral.
The C atom is sp3 in a methane ring, with 4 bond pairs and no solitary pairs of electrons like that. The steric integer is thus 4, and its structure is tetrahedral.
Answer:
2
Explanation:
Carbon Is tetravalent. This means that at any particular point in time, the number of bonds carbon can form at a particular time is 4. Now in this particular question, there is already a double bond between the two carbon atoms. This means that each of the carbon atom has the chance to fulfill it tetra valency by attaching just two bonds to itself.
Hence, to complete the property of its tetra valency, two more bonds needed to be added to the two carbon atoms
