Noble gases are known for having a full outer shell of electrons which helium has as it has two electrons its first electron shell is completely filled
243.92J
Explanation:
Given parameters:
Mass of the aluminum cup = 42.14g
Initial temperature of the cup, t₁ = 20°C
Final temperature of the cup t₂ = 26.41°C
Specific heat capacity of aluminium = 0.903 J g⁻¹ °C⁻¹
Unknown:
Change in heat of the aluminium cup, q = ?
Solution:
The heat lost during the experiment is the heat gained by the aluminum cup.
The quantity of heat is found using the expression below:
q = m C Δt
m is the mass of the cup
C is the specific heat of the cup
Δt is the change in heat
q = 42.14 x 0.903 x (26.41 - 20) = 42.14 x 0.903 x 6.41
q = 243.92J
Learn more:
Specific heat capacity brainly.com/question/7210400
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The balanced equation for the above reaction is as follows;
2H₂ + O₂ --> 2H₂O
stoichiometry of O₂ to H₂O is 1:2
number of O₂ moles reacted - 40.3 g / 32 g/mol = 1.26 mol
according to molar ratio
number of water moles produced = 2 x number of O₂ moles reacted
number of water moles formed - 1.26 x 2 = 2.52 mol
mass of water produced = 2.52 mol x 18 g/mol = 45.4 g
45.4 g of water produced
Answer:
<h2>0.66 atm </h2>
Explanation:
The new pressure can be found by using the formula for Boyle's law which is
where
P1 is the initial pressure
P2 is the final pressure
V1 is the initial volume
V2 is the final volume
Since we're finding the new pressure
We have
We have the final answer as
<h3>0.66 atm</h3>
Hope this helps you
