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nirvana33 [79]
3 years ago
15

Electricity from the local power company costs 7.22 cents/kWh. A homeowner wishes to pay a maximum of 25 cents per month for the

electricity to power a stereo system. For how many hours per month could the stereo system be used?
Physics
2 answers:
mestny [16]3 years ago
7 0
You haven't said how much power the stereo uses.  It matters !

Whatever that number is, the maximum hours per month is

    (3460) divided by (the # of watts the stereo uses when it's playing) .
sammy [17]3 years ago
6 0

Answer:

The power rating of the stereo is not stated and this makes the question incomplete, however, we can make the stereo rating x (this is a basic power calculation)

Explanation:

To calculate the number of hours the homeowner can get,

First, divide the total amount (25cents) by power cost (7.22 cents/kWh) and multiply by 1000 (to convert kilowatt to watt).

This gives us \frac{3462.6W/h}{x} as shown below.

 \frac{25X1000 }{7.22x}= 3462.6/x

Finally, whatever the stereo rating is, insert it as x and solve for the number of hours.

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3 years ago
A charged particle moves at 2.5 × 104 m/s at an angle of 25° to a magnetic field that has a field strength of 8.1 × 10–2 T. If t
nekit [7.7K]

the magnitude of charge=q=8.76 x 10⁻⁵C

Explanation:

the magnetic force Fm is given by

Fm= q V B sinθ

q= charge

v= velocity= 2.5 x 10⁴ m/s

B= magnetic field strength= 8.1 x 10⁻²T

Fm= magnetic force= 7.5 x 10⁻² N

θ=25°

so 7.5 x 10⁻² =q (2.5 x 10⁴ ) (8.1 x 10⁻²) sin25

q=8.76 x 10⁻⁵C

4 0
3 years ago
Read 2 more answers
How many atoms of Pb are there in the compound 3Pbl2
mash [69]

Answer: there are 6 atoms.

Explanation: 3 parts of Pb times 2 atoms per part = 6

good luck:)

5 0
3 years ago
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A long solenoid of radius 3 cm has 1100 turns per meter. If the solenoid carries a current of 1.5 A, then calculate the magnetic
Arada [10]

Answer:

The magnetic field at the center of the solenoid is 2.1  × 10⁻³ T

Explanation:

The magnetic field B at the center of the solenoid is given by

B = μ₀ni where μ₀ = permeability of free space = 4π × 10⁻⁷H/m, n = number of turns per unit length of the solenoid = 1100 turns per meter and i = current in the solenoid = 1.5 A.

So B = μ₀ni

= 4π × 10⁻⁷H/m × 1100 × 1.5 A

= 4π × 10⁻⁷H/m × 1650 A-turns/m

= 20734.5 × 10⁻⁷T  

= 2.07345 × 10⁻³ T

≅ 2.1  × 10⁻³ T

So the magnetic field at the center of the solenoid is 2.1  × 10⁻³ T

3 0
3 years ago
A piston-cylinder device initially contains 0.6 kg of water with a volume of 0.1 m3 . The mass of the piston is such that it mai
Sloan [31]

Answer: Hello the missing piece of your question is attached

question : Determine mass of steam that has entered ( in kg )

answer : 0.206 kg

Explanation:

V1 = 0.1 m^3 ,

v' = V1 / m1 = 0.1 / 0.6 = 0.167 m^3/kg

V2 = 0.2 m^3

using the steam tables

at ; P = 1000 kPa, v' = 0.167 m^3/kg

U1 = 2321  KJ/kg

at ; P = 1000 kPa , T2 = 280°C

v'2= 0.2481 m^3kg

U2 = 2760.6

at ; P = 5MPa ,  T = 500°C

h1 = 3434.7 KJ/Kg

calculate final mass ( m2 )

M2 = V2 / v'2

      = 0.2 / 0.2481 =  0.806 kg

therefore the mass added =  m2 - m1

                                            = 0.806 - 0.6 =  0.206 kg

3 0
3 years ago
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