Question

The output signal from an analogue Internet of Things (IoT) sensor is sampled every 235 µs to convert it into a digital representation. What is the corresponding sampling rate expressed in kHz?
According to the Sampling Theorem (Section 3.3.1), for this sampling rate value, what approximately could be the highest frequency present in the sensor signal, in kHz, assuming the sensor’s lowest frequency is very close to zero?

If each sample is now quantised into 1024 levels, what will be the resulting device output bitrate in kbps?

Give your answer in scientific notation to one decimal place.

Hint: you need to determine the number of bits per sample which allow for 1024 quantisation levels (see Section 2.4, Block 1 and Section 3.3.2, Block 3).

ii.The above IoT sensor is now replaced by a new sensor which has a lowest frequency very close to zero, and a maximum frequency of 3 kHz. Briefly explain how the sampling period of 235 µs used in Part (i) will need to be modified to avoid aliasing in the new sensor’s sampled signal

Answer 1

In order to find the sampling rate per second for 1024 levels and the resulting device output bitrate in kbps, you would get 10kbps

Calculations and Parameters

First, convert from base 10 to base 2

log₂(1024)=log₁₀(1024)/log₁₀(2)

= 3.01029995664/0.301029995664

= 10kbps

Hence, we can note that your question is incomplete so I gave you a general overview to get a better understanding of the concept.

Read more about bit rates here:

brainly.com/question/12977416

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