Yes you balanced it correctly : CH₃CH₂CH₃ ₍g₎ + 5O₂ ₍g₎ -------> 3CO₂ ₍g₎ + 4H₂O ₍g₎
A hack to checking if its correct when they give you the structural formula of one of the species (CH₃CH₂CH₃) is to convert it to the molecular formula and if you get the same answer then it's correct.
So CH₃CH₂CH₃ is the struct-formula for the molec-formula C₃H₈
C₃H₈ + 5O₂ --------> 3 CO₂ + 4H₂O (which means your correct =D)
The primary colors are blue, red, and yellow.
Answer:
The molar mass of the vapor is 43.83 g/mol
Explanation:
Given volume of gas = V = 247.3 mL = 0.2473 L
Temperature = T = 100
= 373 K
Pressure of the gas = P = 745 mmHg (1 atm = 760 mmHg)
![P = \displaystyle \frac{745}{760} \textrm{ atm} = 0.9802 \textrm{ atm}](https://tex.z-dn.net/?f=P%20%3D%20%5Cdisplaystyle%20%5Cfrac%7B745%7D%7B760%7D%20%5Ctextrm%7B%20atm%7D%20%3D%200.9802%20%5Ctextrm%7B%20atm%7D)
Mass of vapor = 0.347 g
Assuming molar mass of gas to be M g/mol
The ideal gas equation is shown below
![\textrm{PV} =\textrm{nRT} \\\textrm{PV} = \displaystyle \frac{m}{M}\textrm{ RT } \\0.98026 \textrm{ atm}\times 0.2473 \textrm{ L} = \displaystyle \frac{3.47 \textrm{ g}}{M}\times 0.0821 \textrm{ L.atm.mol}^{-1}.K^{-1}\times 373\textrm{K} \\M = 43.834 \textrm{ g/mol}](https://tex.z-dn.net/?f=%5Ctextrm%7BPV%7D%20%3D%5Ctextrm%7BnRT%7D%20%5C%5C%5Ctextrm%7BPV%7D%20%3D%20%5Cdisplaystyle%20%5Cfrac%7Bm%7D%7BM%7D%5Ctextrm%7B%20RT%20%7D%20%5C%5C0.98026%20%5Ctextrm%7B%20atm%7D%5Ctimes%200.2473%20%5Ctextrm%7B%20L%7D%20%3D%20%5Cdisplaystyle%20%5Cfrac%7B3.47%20%5Ctextrm%7B%20g%7D%7D%7BM%7D%5Ctimes%200.0821%20%5Ctextrm%7B%20L.atm.mol%7D%5E%7B-1%7D.K%5E%7B-1%7D%5Ctimes%20373%5Ctextrm%7BK%7D%20%5C%5CM%20%3D%2043.834%20%5Ctextrm%7B%20g%2Fmol%7D)
The molar mass of the vapor comes out to be 43.834 g/mol
Answer:
![SO_{3}^{2-}(aq.)+2OH^{-}(aq.)\rightarrow SO_{4}^{2-}(aq.)+H_{2}O(l)+2e^{-}](https://tex.z-dn.net/?f=SO_%7B3%7D%5E%7B2-%7D%28aq.%29%2B2OH%5E%7B-%7D%28aq.%29%5Crightarrow%20SO_%7B4%7D%5E%7B2-%7D%28aq.%29%2BH_%7B2%7DO%28l%29%2B2e%5E%7B-%7D)
Explanation:
The given reaction is an example of oxidation reaction. The step-by-step balancing procedure has been shown below:
Chemical equation: ![SO_{3}^{2-}(aq.)\rightarrow SO_{4}^{2-}(aq.)](https://tex.z-dn.net/?f=SO_%7B3%7D%5E%7B2-%7D%28aq.%29%5Crightarrow%20SO_%7B4%7D%5E%7B2-%7D%28aq.%29)
Balance H and O in basic medium: ![SO_{3}^{2-}(aq.)+2OH^{-}(aq.)\rightarrow SO_{4}^{2-}(aq.)+H_{2}O(l)](https://tex.z-dn.net/?f=SO_%7B3%7D%5E%7B2-%7D%28aq.%29%2B2OH%5E%7B-%7D%28aq.%29%5Crightarrow%20SO_%7B4%7D%5E%7B2-%7D%28aq.%29%2BH_%7B2%7DO%28l%29)
Balance charge: ![SO_{3}^{2-}(aq.)+2OH^{-}(aq.)\rightarrow SO_{4}^{2-}(aq.)+H_{2}O(l)+2e^{-}](https://tex.z-dn.net/?f=SO_%7B3%7D%5E%7B2-%7D%28aq.%29%2B2OH%5E%7B-%7D%28aq.%29%5Crightarrow%20SO_%7B4%7D%5E%7B2-%7D%28aq.%29%2BH_%7B2%7DO%28l%29%2B2e%5E%7B-%7D)
Balanced chemical equation:
![SO_{3}^{2-}(aq.)+2OH^{-}(aq.)\rightarrow SO_{4}^{2-}(aq.)+H_{2}O(l)+2e^{-}](https://tex.z-dn.net/?f=SO_%7B3%7D%5E%7B2-%7D%28aq.%29%2B2OH%5E%7B-%7D%28aq.%29%5Crightarrow%20SO_%7B4%7D%5E%7B2-%7D%28aq.%29%2BH_%7B2%7DO%28l%29%2B2e%5E%7B-%7D)