What’s (10a ^2 )(−6a ^4 ) Simplify
2 answers:
Answer:
Step-by-step explanation:
1) Take out the constants.
2) Simplify 10 × -6 to -60.
3) Use product rule.
4) Simplify 2 + 4 to 6.
<em><u>Therefor</u></em><em><u>,</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>-60a</u></em><em><u>⁶</u></em><em><u>.</u></em>
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Answer:
The correct answer is :
1. Line PQ (One line PQ).
Step-by-step explanation:
The first step to solve this question is to draw the plane A with the points P and Q lying on it.
We know that given two different points there is only one line that contains this two different points.
Let's analyze each option.
''2. Lines PQ and QP''
This option is wrong because there aren't two different lines. In fact it is only one line that can be named line PQ or line QP.
''3. The 2 lines PQ and QP plus another line that does not lie in plane A.''
This option is assuming that exist three lines that contain P and Q. This option is also wrong.
''1. Line PQ''
This option is correct. It will be clarify with the drawing I will attach.
''We can't name them all!''
This option is assuming that exist infinite lines that contain P and Q. This option is wrong.
In the drawing I call the line that contains P and Q as line L.
Given that P and Q lie in plane A necessarily the line L must lie on the plane A.
Answer:
(4,0)
Step-by-step explanation:
The object is first at (0,0)
It is reflected across line x=-2, this means you draw the mirror line at x=-2 and count 2 equal units backwards to get the image.The image will be at ;
The image (-4,0) is then reflected on the y-axis
You know reflection on the y-axis, the y-coordinate remains the same but the x-coordinate is changed to its opposite sign.
Hence;
(- -4,0)= (4,0)
The image will move 8 units towards positive x-axis.This is the same as moving 4 units from the mirror line at (0,0) and land at (4,0)