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Kobotan [32]
2 years ago
5

Express 1 cm3 in m3 please help ​

Mathematics
1 answer:
Oksana_A [137]2 years ago
7 0

Answer:

1E-6 m^3 or 0.000001 m^3

Step-by-step explanation:

1cm^3 = 1cm*1cm*1cm

1m^3 = 100cm*100cm*100cm = 1000000 cm^3

1/1000000 = 1E-6 m^3

Leave a like and mark brainliest if this helped

Leave a like and mark brainliest if this helped

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The difference between two positive integers is 3. If the smaller is added to the square of the larger, the sum is 87.
Komok [63]
Let x be larger integer so x-3 is the smaller
so x^2+ x-3 = 87
x^2 +x -90=0 and factor
(x-9)(x+10)=0
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6 0
3 years ago
Graph each line using intercepts 1/4 x + 2y =2
Leno4ka [110]

The given equation is,

\frac{1}{4}x+2y=2

It can be rewritten in the form of y=mx+c, where c is the y intercept.

Hence,

\begin{gathered} 2y=-\frac{1}{4}x+2 \\ y=\frac{-1}{4\times2}x+\frac{2}{2} \\ y=\frac{-1}{8}x+1 \end{gathered}

Put different values for x and find value of y.

When x=0, y=1.

When x=1,

y=\frac{-1}{8}+1=\frac{7}{8}

The graph is,

5 0
10 months ago
A manufacturing company produces steel housings for electrical equipment. The main component part of the housing is a steel trou
Mrrafil [7]

Answer:

Check the explanation

Step-by-step explanation:

(a)

H0: Population mean = 8.46

H1: Population mean is not equal to 8.46

The test statistic (t) is given by the following expression -

{t=\frac{\overline{x}-\mu_0}{s/\sqrt{n}}}

We have calculated the sample mean (8.421) and sample standard deviation (0.0461). Therefore, the test statistic (t) will be -

t = (8.421 - 8.46)/(0.0461/sqrt(49)) = -5.92

The left-sided critical value from t-distribution (two-tailed) is -2.01. Thus the test statistic falls in the rejection region and we reject the null hypothesis at 95% confidence level and conclude that the population mean is different from 8.46 inches.

(b)

There are the following four assumptions for a single sample t-test.

The observations are in ratio scale.

The observations have been taken in such a manner that every single observation is independent and uncorrelated from the others.

There should not be any significant outliers in the sample observations.

The sample data should be approximately normal.

(c)

The first assumption is true as the data is in inches. The second assumption cannot be tested now. It will depend upon the situation and study design which we assume as correct in this case. The third assumption is checked by plotting a box plot and finding the outliers. The final assumption can be checked using the Anderson-Darling normality test.

Kindly check the graphical table in the attached images below.

(d)

The data is normal (the p-value of Anderson-Darling test in > 0.05). However, two points in the Box plot are outliers though not grossly different from the entire sample data set. So, we conclude that the assumptions are valid in this case for conducting the t-test.

7 0
3 years ago
How can i calculate the growth rate of the values below
Grace [21]

Answer:

  12%

Step-by-step explanation:

The equation for the growth is ...

  f(t) = (initial value)×(growth multiplier per period)^(number of periods)

where the growth multiplier is often expressed as a percentage added to 1:

  multiplier = 1+r

  growth rate = r

__

This equation has two unknowns:

  • initial value
  • growth multiplier

In order to find these, you can make use of two of the supplied data points. I like to choose the ones that are farthest apart, as they tend to average out any errors due to rounding.

Clearly, the table tells you the initial value is 210. If you don't believe, you can put the numbers in the equation to see that:

  f(0) = (initial value)×(growth multiplier)^0

  210 = (initial value)×1

  (initial value) = 210

__

Using the last data point, we get ...

  f(7) = 210×(growth multiplier)^7

  464 = 210×(growth multiplier)^7 . . . . . . . . . fill in table value

  2.209524 = (growth multiplier)^7 . . . . . . .  divide by 210

You can solve this a couple of ways. My calculator is able to take the 7th root, so I can use it to find ...

  \sqrt[7]{2.209524}=\text{(growth multiplier)}\\1.119916\approx \text{(growth multiplier)}

Alternatively, you can use the 1/7 power:

  2.209524^(1/7) = (growth multiplier)

Another way to solve this is to use logarithms:

  log(2.209524) = 7×log(growth multiplier) . . . . . take the log

  log(2.209524)/7 = log(growth multiplier) . . . . . divide by 7

  0.04918553 ≈ log(growth multiplier)

  growth multiplier = 10^0.04918553 ≈ 1.11992 . . . . take the antilog

So, our growth multiplier is ...

  1 + r ≈ 1.11992

  r ≈ .11992 ≈ 12.0%

The rate of growth is about 12% in each period.

_____

Collapsing all of that to a single calculation:

  growth rate = (464/210)^(1/(7-0)) -1 ≈ 12.0%

8 0
3 years ago
Can you help me solve this please
Gekata [30.6K]

Answer:

4

Step-by-step explanation:

4 0
3 years ago
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