<h3>Answer:</h3>
Length: 12 yd
Width: 5.5 yd
<h3>Explanation:</h3>
Let x represent the width of the rectangle in yards. Then 2x+1 can represent the length (double the width plus 1 yard). The area is the product of length and width so we have the relation ...
... x(2x+1) = 66
... 2x² +x -66 = 0
This can be solved using any of several methods. One of them is to factor the equation. To do that, we can look for factors of 2·66 = 132 that differ by 1. Since 132 = 11·12, those are the numbers we're looking for. Then ...
... 2x² +12x -11x -66 = 0 . . . . use our found numbers to rewrite the x term
... 2x(x +6) -11(x +6) = 0 . . . . .factor by grouping
... (2x -11)(x +6) = 0
... x = 11/2 or -6 . . . . . values that make the factors zero. Only the positive value is a useful solution.
... The width of the rectangle is 5.5 yards. Its length is 2·5.5+1 = 12 yards,
P = 2(L + W)
P = 14
W = L - 5
14 = 2(L + L - 5)
14 = 2(2L - 5)
14 = 4L - 10
14 + 10 = 4L
24 = 4L
24/4 = L
6 = L.......the length is 6 inches
W = L - 5
W = 6 - 5
W = 1 <=== the width is 1 inch
# Sin θ = 9/15.
# Cos θ = 12/15.
# Cosec θ = 15/9.
# Sec θ = 5/4
Step-by-step explanation:
Answer:
The most obvious one i can think of would be
x = 13
Step-by-step explanation:
x + 8 = 21
x + 8-8 = 21-8
x = 13
Answer:
yes
Step-by-step explanation:
