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olga nikolaevna [1]
3 years ago
9

Math* please help!!!!

Mathematics
2 answers:
jek_recluse [69]3 years ago
8 0

Answer:

I think its 19.1

Step-by-step explanation:

14 + 5.1

Maybe try

VikaD [51]3 years ago
5 0
We need to use the formula for Area of trapezium.

Area = ((a+b)h)/2

85.95 = ((14+5.1)h)/2
19.1h/2 = 85.95
19.1h = 171.9
h = 171.9/19.1
h = 9
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3 years ago
Find the length of the third side. If necessary, round to the nearest tenth
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\huge\bold{Given:}

Length of the base = 8

Length of the hypotenuse = 17

\huge\bold{To\:find:}

The length of the third side ''x".

\large\mathfrak{{\pmb{\underline{\orange{Solution}}{\orange{:}}}}}

\longrightarrow{\purple{x\:=\: 15}} 

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}

Using Pythagoras theorem, we have

(Perpendicular)² + (Base)² = (Hypotenuse)²

\longrightarrow{\blue{}} {x}^{2} + (8)² = (17)²

\longrightarrow{\blue{}} {x}^{2} + 64 = 289

\longrightarrow{\blue{}}  {x}^{2} = 289 - 64

\longrightarrow{\blue{}}  {x}^{2} = 225

\longrightarrow{\blue{}}  x = \sqrt{225}

\longrightarrow{\blue{}}  x = 15

Therefore, the length of the missing side x is 15.

\huge\bold{To\:verify :}

\longrightarrow{\green{}} (15)² + (8)² = (17)²

\longrightarrow{\green{}} 225 + 64 = 289

\longrightarrow{\green{}} 289 = 289

\longrightarrow{\green{}} L.H.S. = R. H. S.

Hence verified.

\huge{\textbf{\textsf{{\orange{My}}{\blue{st}}{\pink{iq}}{\purple{ue}}{\red{35}}{\green{♨}}}}}

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0.6 + 15b + 4 = 25.6 all equivelant
Mila [183]

Answer:

0.6 + 15b + 4 = 25.6 all equivelant

0.6 + 15b + 4 = 25.6 all equivelant

0.6 + 15b + 4 = 25.6 all equivelant

0.6 + 15b + 4 = 25.6 all equivelant

0.6 + 15b + 4 = 25.6 all equivelant

0.6 + 15b + 4 = 25.6 all equivelant

Step-by-step explanation:

0.6 + 15b + 4 = 25.6 all equivelant

0.6 + 15b + 4 = 25.6 all equivelant

0.6 + 15b + 4 = 25.6 all equivelant

0.6 + 15b + 4 = 25.6 all equivelant

0.6 + 15b + 4 = 25.6 all equivelant

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Line AB contains point A(4,5) and B(9,7). What is the slope of AB
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5/2 



   Your welcome
Your welcome
6 0
3 years ago
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