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Crazy boy [7]
2 years ago
5

Decrease 125 by 40% maths assignment

Mathematics
2 answers:
Afina-wow [57]2 years ago
6 0
<h2><em>HII</em><em>!</em><em>!</em></h2><h2><em>HERE'S</em><em> </em><em>YOUR</em><em> </em><em>ANSWER</em><em> </em></h2><h2 /><h2 /><h2>ANSWER= 75</h2>

<h3><em>STEP</em><em> </em><em>BY</em><em> </em><em>STEP</em><em> </em><em>EXPLANATION</em><em>: </em></h3><h3 />

Decrease number by 40% of its value.

Percentage decrease = 40% × 125

New value

125 - Percentage decrease

125 - (40% × 125)

125 - 40% × 125

(1 - 40%) × 125

(100% - 40%) × 125

60% × 125

60 ÷ 100 × 125

60 × 125 ÷ 100

7,500 ÷ 100

=75

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lyudmila [28]2 years ago
3 0

Answer:

75

Step-by-step explanation:

125 × 0.40 = 50

125 - 50 = 75

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Division of two quantities is expressed as the ____ of those two quantities.
andreev551 [17]


Division of two quantities is expressed as the  quotient of those two quantities.

The word quotient is derived from the Latin language. It is from the Latin word "quotiens" which means "how many times." A quotient  is the answer to a divisional problem. A divisional problem describes how many times a number will go into another. The first time that this word was known to have been used in mathematics was around 1400 - 1500 AD in England.

There are two different ways to find the quotient of two numbers.  One of them is through Fractions. The quotient of a fraction is the number obtained when the fraction is simplified. The other way to find a quotient is  by employing the long division method where the quotient  value is positioned above the divisor and dividend.
 


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3 years ago
If y varies inversely as the square of x and y=4 when x=5, find y when x is 2
Len [333]

need to kind K

Y=k x 1/x^2 = k/x^2

Find K when y=4 & x=5

Y=k/x^2 =

4=k/5^2=

4=k/25

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5 0
3 years ago
From a practice assignment:<br>solve the following differential equation given initial conditions ​
hodyreva [135]

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e^{-y} \, dy = \sin(x) \, dx

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\displaystyle \int e^{-y} \, dy = \int \sin(x) \, dx \implies -e^{-y} = -\cos(x) + C

Use the initial condition to solve for C :

-e^{-0} = -\cos(-\pi) + C \implies -1 = 1 + C \implies C = -2

Then the particular solution to the initial value problem is

-e^{-y} = -\cos(x) - 2 \implies e^{-y} = \cos(x) + 2

(A)

4 0
1 year ago
Rounded to the nearest hundredth, what is the positive solution to the quadratic equation 0 = 2x2 + 3x – 8? Quadratic formula: x
Lynna [10]

ANSWER

1.39

EXPLANATION

The given quadratic equation is

0 = 2 {x}^{2}  + 3x - 8

This is the same as,

2 {x}^{2}  + 3x - 8 = 0

Comparing to

a {x}^{2}  + bx  + c = 0

We have

a=2, b=3,c=-8

Using the quadratic formula, the solution is given by:

x =  \frac{ - b \pm \:  \sqrt{ {b}^{2}  - 4ac} }{2a}

We substitute the values to get,

x =  \frac{ - 3\pm \:  \sqrt{ {3}^{2}  - 4(2)( - 8)} }{2(2)}

x =  \frac{ - 3\pm \:  \sqrt{ 73} }{4}

The positive root is

x =  \frac{ - 3 + \:  \sqrt{ 73} }{4} = 1.39

to the nearest hundredth.

4 0
3 years ago
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sdas [7]
She has to pay $170 i think 
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