Question

Given P(A) = 0.44, P(B) 0.6 and P(An B) = 0.394, find the value of

Answer 1

Given:

$P(A)=0.44,P(B)=0.6,P(A\cap B)=0.394$.

To find:

The value of $P(A\cup B)$, rounding to the nearest thousandth.

Solution:

We know that,

$P(A\cup B)=P(A)+P(B)-P(A\cap B)$

On substituting $P(A)=0.44,P(B)=0.6,P(A\cap B)=0.394$, we get

$P(A\cup B)=0.44+0.6-0.394$

$P(A\cup B)=0.646$

Therefore, the value of $P(A\cup B)$ is 0.646.