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Gwar [14]
3 years ago
8

Water leaves a penstock (the flow path through a hydroelectric dam) at a velocity of 100 ft/s. How deep is the water behind the

dam (in ft). Neglect friction. [h = 155 ft]
Engineering
1 answer:
Marysya12 [62]3 years ago
8 0

Answer:

155fts

Explanation:

We apply the bernoulli's equation to get the depth of water.

We have the following information

P1 = pressure at top water surface = 0

V1 = velocity at too water surface = 0

X1 = height of water surface = h

Hf = friction loss = 0

P2 = pressure at exit = 0

V2 = velocity at exit if penstock = 100ft/s

X2 = height of penstock = 0

g = acceleration due to gravity = 32.2ft/s²

Applying these values to the equation

0 + 0 + h = 0 + v2²/2g +0 + 0

= h = 100²/2x32.2

= 10000/64.4

= 155.28ft

= 155

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Answer:

Explanation:

Hall-Petch equation provides direct relations between the strength of the material and the grain size:

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As in this problem, we don't know the constants of the equation, but we know two properties of the material, we are able to find them from the system of equations:

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Note, that for the given problem, there is no need to convert units to SI, as constants can have any units, which are convenient for us.

From the system of equations calculations, we can find constant: σ0=55.196 MPa, k=18.48 MPa*mm^(0.5)

Now we are able to calculate strength for the grain diameter of 0.004 mm:

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The strength of the steel with the grais size of 0.004 mm is 347.39 MPa.

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