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3 years ago

The pressure exerted by 15m of liquid is 1500pa.The acceleration due to gravity g=10m/s^2.Calculate the density liquid.

Physics

1 answer:

Natali [406]3 years ago

8 0

Answer:

1500 divided by 150(15m x 10m/s^2) = 10

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Answer:

wave

Explanation:

A wave is defined as the disturbance that causes the movement of energy. The energy is transferred as the waves move from one place to another. A medium is required for the transfer of energy. Usually a wave travels through air or water. The process is carried on at a specific speed that is termed as the speed of propagation.

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2 years ago

A woman exerts a constant horizontal force on a large box. As a result, the box moves across a horizontal floor at a constant sp

d1i1m1o1n [39]

Answer:C

Explanation:

When a constant horizontal force is applied to the box, box started moving in the horizontal direction such that it moves with constant velocity $v_0$

Constant velocity implies that net force on the box is zero

i.e. there must be an opposing force which is equal to the applied force and friction force can serve that purpose.

So option c is the correct choice.

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3 years ago

Find an expression for the minimum frictional coefficient needed to keep a car with speed v on a banked turn of radius R designe

solniwko [45]

"v0" means that there are no friction forces at that speed
mgsinΘ = (mv0²/r)cosΘ → the variable m cancels 
sinΘ/cosΘ = tanΘ = v0² / gr
Θ = arctan(v0² / gr) 

When v > v0, friction points downslope: 
mgsinΘ + µ(mgcosΘ + (mv²/r)sinΘ) = (mv²/r)cosΘ → m cancels: 
gsinΘ + µ(gcosΘ + (v²/r)sinΘ) = (v²/r)cosΘ 
µ = ((v²/r)cosΘ - gsinΘ) / (gcosΘ + (v²/r)sinΘ) 
where Θ is defined above. 

When v > v0, friction points upslope: 
mgsinΘ - µ(mgcosΘ + (mv²/r)sinΘ) = (mv²/r)cosΘ → m cancels: 
gsinΘ - µ(gcosΘ + (v²/r)sinΘ) = (v²/r)cosΘ 
µ = (gsinΘ - (v²/r)cosΘ) / (gcosΘ + (v²/r)sinΘ) 
where Θ is defined above.

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3 years ago

When you put the iron cube in the olive oil and the brick cube in the water what loses heat more quickly and why? The oil or the

andrezito [222]

Answer:

HUH

Explanation:

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3 years ago

1. A stationary 50 tonne submarine fires a missile of mass 40kg at

White raven [17]

The velocity of the submarine immediately after firing the missile is 0.0104 m/s

Explanation:

Mass of the submarine M=50 tonne= $50\times 1000=50000kg$

Mass of the missile m=40 kg

velocity of the missile v= 13m/s

we have to calculate the velocity of the submarine after firing

This is the recoil velocity and its expression is derived from the law of conservation of momentum

recoil velocity of the submarine

$V=-mv/M\\=-40\times 13/50000\\=0.0104 m/s$

8 0

3 years ago

The pressure exerted by 15m of liquid is 1500pa.The acceleration due to gravity g=10m/s^2.Calculate the density liquid.​

The pressure exerted by 15m of liquid is 1500pa.The acceleration due to gravity g=10m/s^2.Calculate the density liquid.