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Svetlanka [38]
3 years ago
11

Problem 4: For a conservative force,esvoedca2beee49af123450c68a7237065a45ad885a4229cb932c3697d0b27c6328eaeovse 0N86-C1-52-40-A83

7-22820 If you push a wooden crate across rough ground with a force F over a distance d, what is the potential energy stored in the system due to this force
Physics
1 answer:
natita [175]3 years ago
6 0

Answer:

<em>PE = Fd</em>

Explanation:

Potential energy is the energy possessed by a body by virtue of its position. It is expressed mathematically as:

PE = mgd

m is the mass

g is the acceleration due to gravity

d is the distance

Since Force F is expressed as the product of mass and acceleration due to gravity then, F = mg

Substitute into the formula above:

Recall that: PE = mgd

Since F = mg

PE = Fd

<em>Hence the required expression is PE = Fd</em>

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An excited 92 kg football player celebrates a touchdown by carelessly running straight into the goalpost at 9.4 m/s. He bounces
yKpoI14uk [10]

Answer:

i. 15.6 m/s

ii. I = 1.44 KNs

Explanation:

The impulse, I, on a body is the product of force applied on it and the time it acts.

i.e I = F x t

Impulse is sometimes expressed as the change in momentum of a body. It is measured in Ns.

i. mass, m, of the player = 92 kg

initial velocity of the player, u = 9.4 m/s

final velocity of the player, v = 6.2 m/s

Since he bounces back on hitting the pole, then the sign of initial and final velocities are of opposite sign.

So that,

change in velocity of the player = final velocity - initial velocity

                                          = 6.2 - (-9.4)

                                         = 6.2 + 9.4

                                         = 15.6 m/s

change in velocity of the player is 15.6 m/s

ii. Impulse, I = m(v - u)

                    = 92 x 15.6

                    = 1435.2

Impulse on the player is 1.44 KNs.

7 0
3 years ago
What can you infer about a wave with a long wavelength?
katovenus [111]

Answer:

It has a high frequency

Explanation:

3 0
3 years ago
Read 2 more answers
The diagram below shows a light ray striking Medium A and Medium B at the same angle.
zepelin [54]

Answer: D  Medium B is denser than Medium A because light bends more in Medium B.

Explanation: The more the light bends the less energy it has

6 0
3 years ago
Hydropower stations are almost always attached to dams, holding a large amount of water. But we can't dam air in a similar way t
Alja [10]

Answer:

Advantages of Hydroelectric Energy

1 Renewable

Hydroelectric energy is renewable. This means that we cannot use up. However, there’s only a limited number of suitable reservoirs where hydroelectric power plants can be built and even less places where such projects are profitable.

2 Green

Generating electricity with hydro energy is not polluting itself. The only pollution occurs during the construction of these massive power plants.

3 Reliable

Hydroelectricity is very reliable energy. There are very little fluctuations in terms of the electric power that is being by the plants, unless a different output is desired. Countries that have large resources of hydropower use hydroelectricity as a base load energy source. As long as there is water in the magazines electricity can be generated.

4 Flexible

As previously mentioned, adjusting water flow and output of electricity is easy. At times where power consumption is low, water flow is reduced and the magazine levels are being conserved for times when the power consumption is high.

5 Safe

Compared to among others fossil fuels and nuclear energy, hydroelectricity is much safer. There is no fuel involved (other than water that is).

7 0
3 years ago
In April 1974, Steve Prefontaine completed a 10.0 km race in a time of 27 min , 43.6 s . Suppose "Pre" was at the 7.43 km mark a
Novay_Z [31]

Answer:

Acceleration, a = 0.101 m/s²

Explanation:

Average speed = total distance / total time.

At the 7.43km mark, total distance = 7.43km or 7430m

Total time = 25 * 60 s = 1500s

Average speed = 7430m/1500s = 4.95m/s

He then covers (10 - 7.43)km = 2.57 km = 2570 m

in t = 27m43.6s - 25min = 2m43.6s = 163.6 s

Then he accelerates for 60 s, and maintains this velocity V, for the remaining (163.6 - 60)s = 103.6 s.

From V = u + at; V = 4.95m/s + a *60s

Distance covered while accelerating is

s = ut + ½at² = 4.95m/s * 60s + ½ a *(60s)² = 297m + a*1800s²

Distance covered while at constant velocity, v after accelerating is

D = velocity * time

Where v = 4.95m/s + a*60s

D = (4.95m/s + a*60s) * 103.6s = 512.82m + a*6216s²

Total distance covered after initial 7.43 km, S + D = 2570 m, so

2570 m = 297m + a*1800s² + 512.82m + a*6216s²

2570 = 809.82 + a*8016

a = 809.82m / 8016s² = 0.101 m/s²

8 0
3 years ago
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