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Jlenok [28]
2 years ago
7

Convert 175 lbs to kg (1 kg = 2.2 lbs)

Chemistry
1 answer:
ankoles [38]2 years ago
4 0

Answer:

79.5 kg

Explanation:

Divide 175 by 2.2

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if a scientist creates a new rock like substance in a laboratory, why wouldnt this type of material be classified as a true mine
ad-work [718]
The reason why it is not considered this is because the material was made in a lab, not through nature, which is what is required to be considered as a true mineral.
5 0
2 years ago
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Calculate the molarity of a solution if there are 1.5 mol of NaCl in 2.3 L of solution
frosja888 [35]

Answer:

0.6522 mol/L.

Explanation:

<em>Molarity is defined as the no. of moles of a solute per 1.0 L of the solution.</em>

<em />

M = (no. of moles of solute)/(V of the solution (L)).

<em>∴ M = (no. of moles of solute)/(V of the solution (L)) </em>= (1.5 mol)/(2.3 L) = <em>0.6522 mol/L.</em>

7 0
2 years ago
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Which of the following is chemically inert ( unreactive)?
IrinaK [193]

(C) neon (atomic number 10)

Explanation:

The atom that is chemically inert is Neon with an atomic number of 10.

An atom is chemically inert if it does not willingly take part in chemical reaction.

Atoms takes part in chemical reactions in order to attain a stable configuration as seen in the noble gases.

In the noble gases every enable level is completely filled with the appropriate number of electrons.

  • The noble gases are He, Ne, Ar, Kr, Xe
  • These elements do not react with others.
  • From the given option, Neon is a noble gas and therefore inert.

learn more:

Noble gas brainly.com/question/1781595

#learnwithBrainly

4 0
3 years ago
1. How many milliliters of 10.0 M HNO 3 are needed to prepare 0.350 L of 0.400 M solution?
tatyana61 [14]
<h3>Answer:</h3>

14 milliliters

<h3>Explanation:</h3>

We are given;

  • 10.0 M HNO₃

Prepared solution;

  • Volume of solution as 0.350 L
  • Molarity as 0.40 M

We are required to determine the initial volume of HNO₃

  • We are going to use the dilution formula;
  • The dilution formula is;

M₁V₁ = M₂V₂

Rearranging the formula;

V₁ = M₂V₂ ÷ M₁

    =(0.40 M × 0.350 L) ÷ 10.0 M

   = 0.014 L

But, 1 L = 1000 mL

Therefore,

Volume = 14 mL

Thus, the volume of 10.0 M HNO₃ is 14 mL

5 0
2 years ago
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