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Orlov [11]
3 years ago
14

How many molecules are in 2.00 moles of H20????????

Chemistry
1 answer:
Elis [28]3 years ago
7 0

2x 6.022x10^23= 1.204x10^24

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Approximately how old is the Sun?
malfutka [58]
The answer is C. 4.6 billion years. Hoped I helped. :)
5 0
3 years ago
Read 2 more answers
2. The approximate concentration of hydrochloric acid, HCl, in the stomach (stomach
Sergio039 [100]

Answer:

a) 0.714g of bicarbonate of soda are required.

b) 0.221g of Al(OH)₃ are required

Explanation:

The reactions of HCl with bicarbonate of soda and aluminium hydroxide are:

HCl + NaHCO₃ → H₂O + NaCl + CO₂

3 HCl + Al(OH)₃ → 3H₂O + AlCl₃

The moles of HCl that we need neutralize are:

50mL = 0.050L * (0.17mol / L) = 0.0085 moles HCl

To solve these problem we need to find the moles of the antacid using the chemical reaction and its mass using its molar mass;

<em>a) </em><em>Moles NaHCO₃ = Moles HCl = 0.0085 moles </em>

The mass is -Molar mass NaHCO₃: -84g/mol-

0.0085 moles * (84g / mol) = 0.714g of bicarbonate of soda are required

b) 0.0085 moles HCl * (1mol Al(OH)₃ / 3mol HCl) = 2.83x10⁻³ moles Al(OH)₃

The mass is -Molar mass: 78g/mol-:

2.83x10⁻³ moles Al(OH)₃ * (78g/mol) =

<h3>0.221g of Al(OH)₃ are required</h3>
5 0
2 years ago
A mixture containing nitrogen and hydrogen weighs 3.49 g and occupies a volume of 7.45 L at 305 K and 1.03 atm. Calculate the ma
-BARSIC- [3]

Answer:

Mass percent N₂ = 89%

Mass percent H₂ = 11%

Explanation:

First we <u>use PV=nRT to calculate n</u>, which is the total number of moles of nitrogen and hydrogen:

  • 1.03 atm * 7.45 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 305 K
  • n = 0.307 mol

So now we know that

  • MolH₂ + MolN₂ = 0.307 mol

and

  • MolH₂ * 2 g/mol + MolN₂ * 28 g/mol = 3.49 g

So we have a <u>system of two equations and two unknowns</u>. We use algebra to solve it:

Express MolH₂ in terms of MolN₂:

  • MolH₂ + MolN₂ = 0.307 mol
  • MolH₂ = 0.307 - MolN₂

Replace that value in the second equation:

  • MolH₂ * 2 g/mol + MolN₂ * 28 g/mol = 3.49
  • (0.307-MolN₂) * 2 + MolN₂ * 28 = 3.49
  • 0.614 - 2MolN₂ + 28molN₂ = 3.49
  • 0.614 + 26MolN₂ = 3.49
  • MolN₂ = 0.111 mol

Now we calculate MolH₂:

  • MolH₂ + MolN₂ = 0.307 mol
  • MolH₂ + 0.111 = 0.307
  • MolH₂ = 0.196 mol

Finally, we convert each of those mol numbers to mass, to <u>calculate the mass percent</u>:

  • N₂ ⇒ 0.111 mol * 28 g/mol = 3.108 g N₂
  • H₂ ⇒ 0.196 mol * 2 g/mol = 0.392 g H₂

Mass % N₂ = 3.108/3.49 * 100% = 89.05% ≅ 89%

Mass % H₂ = 0.392/3.49 * 100% = 11.15% ≅ 11%

5 0
3 years ago
C3H8 and CH4 are 2 compounds made from the same elements. This is an example of which law? A) Law of Conservation of Mass b) Law
Sphinxa [80]

C3H8 and CH4 are two compounds made from the same two elements, C and H. The ratios of C and H for both are round numbers.

Law of multiple proportions states that when two elements combine with each other to form more than one compound, the weights of one element that combine with a fixed weight of the other are in a ratio of small whole numbers.

So the ans is C) Law of Multiple Proportions

6 0
3 years ago
When 55.0 grams of metal at 75.0°C is added to 100. grams of water at 15.0°C, the temperature of the water rises to 18.7°C. Assu
olga2289 [7]

Answer:

The specific heat of the metal is 0,50 J/gºC

Explanation:

Assume that no heat is lost to the surroundings

(Q = m . C . ΔT)metal + (Q = m . C . ΔT)water = 0

Let's replace our values.

55g . C . (18,7ºC - 75ºC) + 100g . 4,184 J/g·°C . (18,7ºC - 15ºC) = 0

55g . C . -56,3 ºC + 418,4J/·°C . 3,7ºC = 0

-3096,5 gºC . C + 1548,08 J = 0

1548,08 J = 3096,5 gºC . C

1548,08 J / 3096,5 gºC  = C = 0,50 J/gºC

8 0
3 years ago
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