Answer:
a. CO2 and H20
Explanation:
Chemically, this combustion process consists of a reaction between methane and oxygen in the air. When this reaction takes place, the result is carbon dioxide (CO2), water (H2O), and a great deal of energy. The following reaction represents the combustion of methane:
CH4[g] + 2 O2[g] -> CO2[g] + 2 H2O[g] + energy
One molecule of methane, (the [g] referred to above means it is gaseous form), combined with two oxygen molecules, react to form a carbon dioxide molecule, and two water molecules usually given off as steam or water vapor during the reaction and energy.
Answer:
The rate equation for this reaction:
Explanation:
Decomposition of ammonia:
Rate law of the can be written as;
1) Rate of the reaction , when
..[1]
2) Rate of the reaction , when
..[2]
[1] ÷ [2]
On solving for x , we get ;
x = 0
The rate equation for this reaction:
<u>Answer:</u> The rate of heat flow is 3.038 kW and the rate of lost work is 1.038 kW.
<u>Explanation:</u>
We are given:
Rate of flow of ideal gas , n = 4 kmol/hr = (Conversion factors used: 1 kmol = 1000 mol; 1 hr = 3600 s)
Power produced = 2000 W = 2 kW (Conversion factor: 1 kW = 1000 W)
We know that:
(For isothermal process)
So, by applying first law of thermodynamics:
.......(1)
Now, calculating the work done for isothermal process, we use the equation:
where,
= change in work done
n = number of moles = 1.11 mol/s
R = Gas constant = 8.314 J/mol.K
T = temperature = 475 K
= initial pressure = 100 kPa
= final pressure = 50 kPa
Putting values in above equation, we get:
Calculating the heat flow, we use equation 1, we get:
[ex]\Delta q=3.038kW[/tex]
Now, calculating the rate of lost work, we use the equation:
Hence, the rate of heat flow is 3.038 kW and the rate of lost work is 1.038 kW.
Answer:
Explanation:
Hello,
In this case, we use the Avogadro's number to compute the molecules of C2F4 whose molar mass is 100 g/mol contained in a 485-kg sample as shown below:
Best regards,