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KonstantinChe [14]

3 years ago

13

Convert 3/5 to a decimal using long division

1 answer:

NISA [10]3 years ago

8 0

Step-by-step explanation:

5✓3

0.6

put a zero in 3and put a zero above put a decimal point and 6 because of 30

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Which of the following numbers are perfect squares? <br> 27<br> 36<br> 81<br> 108<br> 121

romanna [79]

36, 81, and 121 are all perfect squares

5 0

3 years ago

Read 2 more answers

Hellooopppppppppppppppp

schepotkina [342]

Answer:

150.88

Step-by-step explanation:

just gotta fine the area for each square using the formula base times height with a good old calculator and add them all together, hopefully that's correct

7 0

3 years ago

Bezzdna [24]

Jerome bought C. $4\frac{7}{8}$ pounds of candy.

Step-by-step explanation:

Step 1:

First, we must convert the mixed fractions into improper fractions. To do that we multiply the whole number with the denominator and add with it the numerator while the denominator remains the same.

To convert this fraction $1\frac{1}{2} = \frac{(1)(2)+1}{2} =\frac{3}{2} .$

To convert this fraction $2\frac{3}{4} = \frac{(2)(4)+3}{4} =\frac{11}{4} .$

So Jerome bought $\frac{3}{2}$ pounds of jelly beans, $\frac{5}{8}$ pounds of gumballs and $\frac{11}{4}$ pounds of chocolate.

Step 2:

We add all the values to determine the total candy bought.

$\frac{3}{2} +\frac{5}{8} + \frac{11}{4} = \frac{(4(3)+1(5)+2(11))}{8} .$

$\frac{(4(3)+1(5)+2(11))}{8} = \frac{39}{8} .$

$\frac{39}{8}$ can also be written as $4\frac{7}{8}$ .

So Jerome bought $4\frac{7}{8}$ pounds of candy which is option C.

6 0

4 years ago

Prove algebraically what type of function this is (even, odd, or neither).<br>f(x) = x^6 – x^4

Savatey [412]

Let's see.

We have function $f(x)=x^6-x^4$ . We have to determine if the function is even or odd or neither.

We can find this out in many ways but the assignment specifically asks to prove this algebraically.

Function is even if $f(x)=f(-x)$ , so, $x^6-x^4=(-x)^6-(-x)^4$

Which is true since negative raised to an even power is positive to that same number.

Similarly, function is odd if $f(x)=-f(-x)$ , that is,

$x^6-x^4\neq-((-x)^6-(-x)^4)$ .

So we have prooved that function $f(x)$ is an even function not an odd function and therefore also not neither.

Hope this helps.

3 0

4 years ago

It’s for music please someone help

Alchen [17]

Answer:

Yes

Step-by-step explanation:

The conductor will beat the pattern(hope this helps)

4 0

3 years ago