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4 years ago

Which of the following elements has the highest first ionization energy: Na, Mg, S or Cl?

Chemistry

1 answer:

storchak [24]4 years ago

3 0

Answer:

Cl has the highest ionization energy because all these elements lie in the same period and ionization energy increases from left to right across a period as Cl is the at the last in this period so it has the highest ionization energy

Explanation:

I hope it will help you:)

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Evidence of chemical reactions include -

Ludmilka [50]

Answer:

I think it's light production, color change (new/different), gas production (bubbles/fizzing - not boiling), precipitate, and temperature change

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3 years ago

Calculate the enthalpy change, ΔH, for the process in which 30.1 g of water is converted from liquid at 10.1 ∘C to vapor at 25.0

gayaneshka [121]

You can split the process in two parts:

1) heating the liquid water from 10.1 °C to 25.0 °C , and

2) vaporization of liquid water at constant temperature of 25.0 °C.

For the first part, you use the formula ΔH = m*Cs*ΔT

ΔH = 30.1g * 4.18 j/(g°C)*(25.0°C - 10.1°C) = 1,874 J

For the second part, you use the formula ΔH = n*ΔHvap

Where n is the number of moles, which is calculated using the mass and the molar mass of the water:

n = mass / [molar mass] = 30.1 g / 18.0 g/mol = 1.67 mol

=> ΔH = 1.67 mol * 44,000 J / mol = 73,480 J

3) The enthalpy change of the process is the sum of both changes:

ΔH total = 1,874 J + 73,480 J = 75,354 J

Answer: 75,354 J

7 0

3 years ago

Phương trình hóa học là gì

Doss [256]

Explanation:

sự xuất bản hóa học nào? có một câu hỏi về khoa học mà bạn cần giúp đỡ? tôi luôn ở đây để giúp đỡ!

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3 years ago

A reaction occurs in which hydrogen-1 and hydrogen-2 form helium-3. Is this a chemical reaction or a nuclear reaction, and how d

olga nikolaevna [1]

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3 years ago

How many grams of sodium chromate, Na2CrO4, are needed to react completely with

JulsSmile [24]

Answer:

We need 27.0 grams of Na2CrO4 to react with 56.7 grams of AgNO3

Explanation:

Step 1: data given

Mass of silver nitrate AgNO3 = 56.7 grams

Molar mass AgNO3 = 169.87 g/mol

Molar mass of Na2CrO4 = 161.97 g/mol

Step 2: The balanced equation

2AgNO3 + Na2CrO4 → Ag2CrO4 + 2NaNO3

Step 3: Calculate moles AgNO3

Moles AgNO3 = mass AgNO3 / molar mass AgNO3

Moles AgNO3 = 56.7 grams / 169.87 g/mol

Moles AgNO3 = 0.334 moles

Step 4: Calculate moles Na2CrO4 moles needed

For 2 moles AgNO3 we need 1 mol Na2CrO4 to produce 1 mol Ag2CrO4 and 2 moles NaNO3

For 0.334 moles AgNO3 we need 0.334 / 2 = 0.167 moles Na2CrO4

Step 5: Calculate mass Na2CrO4

Mass Na2CrO4 = 0.167 moles * 161.97 g/mol

Mass Na2CrO4 = 27.0 grams

We need 27.0 grams of Na2CrO4 to react with 56.7 grams of AgNO3

8 0

3 years ago