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rewona [7]
3 years ago
9

What is the volume of a sphere with a radius of 6in? Round to the nearest hundredth. Remember V = 4/3πr3 * 20 points 457.86 inch

es cubed 394.56 inches cubed 904.78 inches cubed 807.78 inches cubed
Mathematics
1 answer:
kakasveta [241]3 years ago
7 0

Given:

The radius of the sphere is 6 in.

To find:

The volume of the sphere.

Solution:

We know that, the volume of a sphere is

V=\dfrac{4}{3}\pi r^3

Where, r is the radius of the sphere.

Putting r=6, we get

V=\dfrac{4}{3}\pi (6)^3

V=\dfrac{4}{3}\pi (216)

V=288\pi

V\approx 904.78

The volume of the sphere is 904.78 inches cubed.

Therefore, the correct option is C.

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An airline experiences a no-show rate of 6%. What is the maximum number of reservations that it could accept for a flight with a
LekaFEV [45]

Let Xb be the number of reservations that are accommodated. Xb has the binomial distribution with n trials and success probability p = 0.94

In general, if X has the binomial distribution with n trials and a success probability of p then
P[Xb = x] = n!/(x!(n-x)!) * p^x * (1-p)^(n-x)
for values of x = 0, 1, 2, ..., n
P[Xb = x] = 0 for any other value of x.

To use the normal approximation to the binomial you must first validate that you have more than 10 expected successes and 10 expected failures. In other words, you need to have n * p > 10 and n * (1-p) > 10.

Some authors will say you only need 5 expected successes and 5 expected failures to use this approximation. If you are working towards the center of the distribution then this condition should be sufficient. However, the approximations in the tails of the distribution will be weaker espeically if the success probability is low or high. Using 10 expected successes and 10 expected failures is a more conservative approach but will allow for better approximations especially when p is small or p is large.

If Xb ~ Binomial(n, p) then we can approximate probabilities using the normal distribution where Xn is normal with mean μ = n * p, variance σ² = n * p * (1-p), and standard deviation σ

I have noted two different notations for the Normal distribution, one using the variance and one using the standard deviation. In most textbooks and in most of the literature, the parameters used to denote the Normal distribution are the mean and the variance. In most software programs, the standard notation is to use the mean and the standard deviation.

The probabilities are approximated using a continuity correction. We need to use a continuity correction because we are estimating discrete probabilities with a continuous distribution. The best way to make sure you use the correct continuity correction is to draw out a small histogram of the binomial distribution and shade in the values you need. The continuity correction accounts for the area of the boxes that would be missing or would be extra under the normal curve.

P( Xb < x) ≈ P( Xn < (x - 0.5) )
P( Xb > x) ≈ P( Xn > (x + 0.5) )
P( Xb ≤ x) ≈ P( Xn ≤ (x + 0.5) )
P( Xb ≥ x) ≈ P( Xn ≥ (x - 0.5) )
P( Xb = x) ≈ P( (x - 0.5) < Xn < (x + 0.5) )
P( a ≤ Xb ≤ b ) ≈ P( (a - 0.5) < Xn < (b + 0.5) )
P( a ≤ Xb < b ) ≈ P( (a - 0.5) < Xn < (b - 0.5) )
P( a < Xb ≤ b ) ≈ P( (a + 0.5) < Xn < (b + 0.5) )
P( a < Xb < b ) ≈ P( (a + 0.5) < Xn < (b - 0.5) )

In the work that follows X has the binomial distribution, Xn has the normal distribution and Z has the standard normal distribution.

Remember that for any normal random variable Xn, you can transform it into standard units via: Z = (Xn - μ ) / σ

In this question Xn ~ Normal(μ = 0.94 , σ = sqrt(0.94 * n * 0.06) )

Find n such that:

P(Xb ≤ 160) ≥ 0.95

approximate using the Normal distribution
P(Xn ≤ 160.5) ≥ 0.95

P( Z ≤ (160.5 - 0.94 * n) / sqrt(0.94 * n * 0.06)) ≥ 0.95

P( Z < 1.96 ) ≥ 0.95

so solve this equation for n

(160.5 - 0.94 * n) / sqrt(0.94 * n * 0.06) = 1.96

n = 164.396

n must be integer valued so take the ceiling and you have:

n = 165.

The air line can sell 165 tickets for the flight and accommodate all reservates at least 95% of the time

If you can understand that...

7 0
3 years ago
Find the variable x.
Mazyrski [523]

Answer:

x = 5

Step-by-step explanation:

7x is a secant- secant angle and has measure equal to half the difference of the intercepted arcs, that is

7x = 0.5(22x + 10 - 50)

7x = 0.5(22x - 40) ← distribute

7x = 11x - 20 ( subtract 11x from both sides )

- 4x = - 20 ( divide both sides by - 4 )

x = 5

5 0
3 years ago
If y=kx, where k is a constant, and y=24 when x=6, what is the value of y when x=5?A. 6B. 15C. 20D. 23
Marizza181 [45]

First, we will find the value of k

We can do this by sybstituting y=24, x=6 in;

y=kx and then solve for k

24= k(6)

divide both-side of the equation by 6

24/6 = k

4 = k

k=4

Then when x = 5, we will substitute x=5 and k=4 in; y=kx and then solve for y

y= (4)(5)

y = 20

7 0
1 year ago
What is the quotient of (2x3 – 29x + 13) ÷ (x + 4)?
sleet_krkn [62]

9514 1404 393

Answer:

  C.  2x^2 -8x +3 +1/(x +4)

Step-by-step explanation:

Synthetic division is useful for finding the quotient. Or, you can use polynomial long division. The result is the same, but synthetic division requires less writing.

7 0
3 years ago
Please help first answer will be marked brainiest
Tresset [83]

Answer:

6x

Step-by-step explanation:

add sides up

5 0
3 years ago
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