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rewona [7]
3 years ago
9

What is the volume of a sphere with a radius of 6in? Round to the nearest hundredth. Remember V = 4/3πr3 * 20 points 457.86 inch

es cubed 394.56 inches cubed 904.78 inches cubed 807.78 inches cubed
Mathematics
1 answer:
kakasveta [241]3 years ago
7 0

Given:

The radius of the sphere is 6 in.

To find:

The volume of the sphere.

Solution:

We know that, the volume of a sphere is

V=\dfrac{4}{3}\pi r^3

Where, r is the radius of the sphere.

Putting r=6, we get

V=\dfrac{4}{3}\pi (6)^3

V=\dfrac{4}{3}\pi (216)

V=288\pi

V\approx 904.78

The volume of the sphere is 904.78 inches cubed.

Therefore, the correct option is C.

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Solve the inequality 3x-1>-6x​
Ghella [55]

Answer:

x > 1/9

Step-by-step explanation:

Given that:

3x-1>-6x​

Adding 6x + 1 on both sides we get

3x-1 + 6x + 1>-6x​ + 6x +1

3x +  6x > 1

Adding both variables

9x > 1

Dividing both sides b 9 we get

9x/9 > 1/9

x > 1/9

I hope it will help you!​

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3 years ago
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RideAnS [48]
It's the last one. 15/2 is 7.5.

Therefore you must do the same to the 9. Divide 9 by 7.5 To give you 1.2 and that's your answer.
8 0
3 years ago
A box weighs 90 grams.<br>Write down, in terms of b, the weight of b boxes.​
Drupady [299]

Answer:

Let B = the weight of box B

Let 2B = the weight of box A

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B + 2B + 2B + 30 = 640

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2B = 2(122) = 244 pounds, weight of box A

2B + 30 = 2(122) + 30 = 274 pounds, weight of box C

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3 years ago
Please answer this question now
IrinaVladis [17]

Answer:

243.75

I hope i am right

Step-by-step explanation:

Using \: angle\: 40 \\Opposite = 25\\Hypotenuse = ?\\Sin \alpha = \frac{opp}{hyp} \\Sin 40 = \frac{25}{x} \\0.6427= \frac{25}{x}\\0.6427x = 25\\x = \frac{25}{0.6427}\\ x = 38.89\\x = 39\\Using \:Pythagoras\: theorem\\Hyp^2 = Opp^2 +Adj ^2\\39^2=25^2+x^2\\1521=625+x^2\\1521-65=x^2\\896=x^2\\x=29.93\\x = 30\\area = 1/2 \times b \times c \times sin(A).\\b =25\\c =39\\a =30\\A = \frac{1}{2} \times 25  \times 39 \times Sin 30\\A = 487.5\times 1/2\\A =243.75yd^2

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sveta [45]

Answer:

2.16

Step-by-step explanation:

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