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pishuonlain [190]
3 years ago
12

If an object had a negative velocity, then it must be travelingNorthUpEastSouth​

Physics
1 answer:
alexgriva [62]3 years ago
8 0

Answer:

im not sure which way the object was supposer to be traveling but a negative velocity means its going backwards

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Dierdre drew a diagram to compare the three types of mirrors.
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<em>Labels that belong in the marked ares X, Y & Z include;</em>

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Y: Image may be smaller than object

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Does anyone know the answers to these ?
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The process by which green plants convert light energy from the sun into chemical energy and food for use is known as - blank-
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Answer:

Photosynthesis

Explanation:

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3 years ago
What would happen if you use a thicker wire around the iron nail of an electromagnet? (thats the whole question)
puteri [66]

Answer:

When we have a current I, we will have a magnetic field perpendicular to this current.

Then if we have a wire in a "spring" form. then we will have a magnetic field along the center of this "spring".

Now suppose we put an iron object in the middle (where the magnetic field is) then we will magnetize the iron object.

Of course, the intensity of the magnetic field is proportional to the current, given by:

B = (μ*I)/(2*π*r)

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Now remember that for a resistor:

R = ρ*L/A

R is the resistance, ρ is the resistivity, which depends on the material of the wire, L is the length of the wire, and A is the cross-section of the wire.

If we increase the area of the wire (if we use a thicker wire).

And the relation between resistance and current is:

I = V/R

Where V is the voltaje.

Now, if we use a thicker wire, then the cross-section area of the wire increases.

Notice in the resistance equation, that the cross-section area is on the denominator, then if we increase the area A, the resistance decreases.

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3 0
3 years ago
The electric potential ( relative to infinity ) due to a single point charge Q is 400 V at a point that is 0.6 m to the right of
UkoKoshka [18]

Answer:

The potential at a distance of 0.9 m is 266.67 V.

Explanation:

Charge = Q

Potential is 400 V at a distance 0.6 m .

Let the potential is V at a distance 0.9 m.

Use the formula of potential.

V = \frac{Kq}{r}\\\\\frac{V}{400}=\frac{0.6}{0.9}\\\\V = 266.67 V

5 0
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