Calculate the angular velocity of the earth in its orbit around the sun and about its axis.

1 answer:

8 0

A delightful problem !

I'm pretty sure that what we need here is the speeds, not the velocities,
and that's the way I'm going to do it.

Regular speed is (distance covered) divided by (time to cover the distance) .

Angular speed is very much the same.
It's
 (angle turned) divided by (time to turn the angle) .

Earth's orbit around the sun:

..... Once per year.
..... Roughly 360° in 365 days ..... almost exactly 1° per day.
Let's see what it is more accurately:

 (360°) / (365.25636 days) = 0.985609° per day.

============================================

Earth's rotation on its axis:

..... Once per "day".
..... Roughly 360° in 24 hours ..... almost exactly 15° per hour.

This one is slightly trickier to do more accurately, because a day is
not necessarily 24 hours. It depends on what you call 1 day.

-- If you say the day is the period of time between when the sun is
highest in the sky, then that averages out to 24 hours in the course
of a year.

-- If you say that the day is the period of time it takes for a star
to reach the same point in the sky tomorrow night, then that's 

 23 hours, 56 minutes, 4.09 seconds .

Using this to calculate the angular speed of rotation, you get

 (360°) / (23h 56m 4.09s) = 15.041° per hour

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At a point 1.2 m out from the hinge, 14.0 N force is exerted at an angle of 27 degrees to the moment arm in a plane which is per

geniusboy [140]

Answer:

$\tau = 7.63 Nm$

Explanation:

As we know that moment of force is given as

$\tau = \vec r \times \vec F$

now we have

$\vec r = 1.2 m$

$\vec F = 14 N$

now from above formula we have

$\tau = r F sin\theta$

here we know that

$\theta = 27 degree$

so we have

$\tau = (1.2)(14) sin27$

$\tau = 7.63 Nm$

3 0

2 years ago

WILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!!

faust18 [17]

Answer:

9)a

10) I think true

11)b

Explanation:

9)a. because it's told that the car is slowing down, the sum of the forces that are towards left, should be more than the ones that are towards right. if the car was gaining speed, "b" would have been correct. and if it was told that the car is moving without a change in the speed, "c" would have been correct.

10) if a moving object has a change of speed or direction, it would have an acceleration. now if a moving object experiences an unbalanced force, it'd either slow down, gain speed or change direction, and in all of the three possibilities it'd have an acceleration.

11) upward and downward forces are equal, and the sum of them would be 0N(because they have opposite directions). so they negate each other.

and the rightward force is 5N more than the leftward force. so the Net Force would be 5N.

-30+30-10+15=5N

if it is unclear or you need more explanation, ask freely.

8 0

3 years ago

g a small smetal sphere, carrying a net charge is held stationarry. what is the speed are 0.4 m apart

weeeeeb [17]

Complete Question

A small metal sphere, carrying a net charge q1=−2μC, is held in a stationary position by insulating supports. A second small metal sphere, with a net charge of q2= -8μC and mass 1.50g, is projected toward q1. When the two spheres are 0.80m apart, q2 is moving toward q1 with speed 20ms−1. Assume that the two spheres can be treated as point charges. You can ignore the force of gravity.The speed of q2 when the spheres are 0.400m apart is.

Answer:

The value $v_2 = 4 \sqrt{10} \ m/s$