Calculate the angular velocity of the earth in its orbit around the sun and about its axis.

1 answer:

8 0

A delightful problem !

I'm pretty sure that what we need here is the speeds, not the velocities,
and that's the way I'm going to do it.

Regular speed is (distance covered) divided by (time to cover the distance) .

Angular speed is very much the same.
It's
 (angle turned) divided by (time to turn the angle) .

Earth's orbit around the sun:

..... Once per year.
..... Roughly 360° in 365 days ..... almost exactly 1° per day.
Let's see what it is more accurately:

 (360°) / (365.25636 days) = 0.985609° per day.

============================================

Earth's rotation on its axis:

..... Once per "day".
..... Roughly 360° in 24 hours ..... almost exactly 15° per hour.

This one is slightly trickier to do more accurately, because a day is
not necessarily 24 hours. It depends on what you call 1 day.

-- If you say the day is the period of time between when the sun is
highest in the sky, then that averages out to 24 hours in the course
of a year.

-- If you say that the day is the period of time it takes for a star
to reach the same point in the sky tomorrow night, then that's 

 23 hours, 56 minutes, 4.09 seconds .

Using this to calculate the angular speed of rotation, you get

 (360°) / (23h 56m 4.09s) = 15.041° per hour

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a toy propeller fan with a moment of inertia of .034 kg x m^2 has a net torque of .11Nxm applied to it. what angular acceleratio

Harman [31]

Answer:

The angular acceleration is $\alpha = 3.235 \ rad/s ^2$

Explanation:

From the question we are told that

The moment of inertia is $I = 0.034\ kg \cdot m^2$

The net torque is $\tau = 0.11\ N \cdot m$

Generally the net torque is mathematically represented as

$\tau = I * \alpha$

Where $\alpha$ is the angular acceleration so

$\alpha = \frac{\tau }{I}$

substituting values

$\alpha = \frac{0.1 1}{ 0.034}$

$\alpha = 3.235 \ rad/s ^2$

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A submarine is stranded on the bottom of the ocean with its hatch 21.0 m below the surface. calculate the force (in n) needed to

Tanzania [10]

Answer:

28,400 N

Explanation:

Let's start by calculating the pressure that acts on the upper surface of the hatch. It is given by the sum of the atmospheric pressure and the pressure due to the columb of water, which is given by Stevin's law:

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