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3 years ago

9(6k + 3r)= A) 15k+12rB) 54k+27rC) 6(3k+0rD) 3(18k+9r

Mathematics

2 answers:

Nadusha1986 [10]3 years ago

4 0

Hopes this helps:

Answer: B 54k + 27r

Please mark as brainlist

tensa zangetsu [6.8K]3 years ago

3 0

Answer:

Step-by-step explanation:

9*6k+9*3r

54k+27r so the answer is B

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Step-by-step explanation:

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3 years ago

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3 years ago

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What is the explicit rule for the geometric sequence?<br> 600, 300, 150, 75, ...

pochemuha

Answer:

Step-by-step explanation:

Hello, this is a geometric sequence so we are looking for a multiplicative factor.

$a_0=600\\\\a_1=a_0 \cdot \boxed{\dfrac{1}{2}} = 300 = 600 \cdot \boxed{\dfrac{1}{2}}\\\\a_2=a_1 \cdot \boxed{\dfrac{1}{2}} = 150= 300 \cdot \boxed{\dfrac{1}{2}}\\\\a_3=a_2 \cdot \boxed{\dfrac{1}{2}} = 75 = 150 \cdot \boxed{\dfrac{1}{2}}$

So, the explicit formula is for n

$\boxed{a_n=a_0\cdot \left(\dfrac{1}{2}\right)^n=600\cdot \left(\dfrac{1}{2}\right)^n}}$

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3 years ago

If x / 2y = 0.4 , A / 5B = 0.25 Then A + y / 5 =…....

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Answer:

$\frac{x}{2y} = \frac{4}{10} \\ 8y = 10x \\ y = \frac{10x}{8} - - - - - 1 \\ \\ \frac{a}{5b} = \frac{25}{100} \\ \frac{a}{5b} = \frac{1}{4} \\ 4a = 5b \\ a = \frac{5b}{4} - - - 2 \\ \\ so \: \: \frac{a + y}{5} \\ = (a + y) \times \frac{1}{5} \\ = ( \frac{5b}{4} + \frac{5x}{4} ) \times \frac{1}{5} \\ = \frac{5b + 5x}{4} \times \frac{1}{5} \\ = \frac{5(b + x)}{4} \times \frac{1}{5} \\ = \frac{b + x}{4} \\ \\ so \: \: \: \frac{a + y}{5} = \frac{b + x}{4}$

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3 years ago

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3 years ago

9(6k + 3r)= A) 15k+12rB) 54k+27rC) 6(3k+0rD) 3(18k+9r​

9(6k + 3r)= A) 15k+12rB) 54k+27rC) 6(3k+0rD) 3(18k+9r