This assignment is hard as heck lol!

Mathematics

1 answer:

Elina [12.6K]3 years ago

3 0

Answer:

z = 3 $\sqrt{13}$

Step-by-step explanation:

Using the altitude- on- hypotenuse theorem

( leg of large Δ )² = ( part of hypotenuse below it ) × ( whole hypotenuse )

z² = 9 × (9 + 4) = 9 × 13 = 117 ( take square root of both sides )

z = $\sqrt{117}$

= $\sqrt{9(13)}$

= $\sqrt{9}$ × $\sqrt{13}$

= 3 $\sqrt{13}$

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The area of the rug is 4 15/36<br> The rug is 2 3/4 meters in height <br> How wide is the rug

sineoko [7]

I assume the rug is rectangle.

The area of rectangle is width (W) multiply by hight (H)

$A=4\frac{15}{36}=4\frac{5\cdot3}{12\cdot3}=4\frac5{12}\\\\H=2\frac34\\\\\\A=W\cdot H\\\\4\frac{5}{12}=W\cdot2\frac34\\\\4\frac5{12}:2\frac34=W\\\\ \frac{4\cdot12+5}{12}:\frac{2\cdot4+3}{4}=W\\\\ \frac{53}{12}:\frac{11}4=W\\\\ \frac{53}{12}\cdot\frac4{11}=W\\\\ \frac{53\cdot4}{3\cdot4\cdot11}=W\\\\W=\frac{53}{33}\\\\W=1\frac{20}{33}$

The rug is $1\frac{20}{33}$ meters wide