Answer:
9000 kg/m³
Explanation:
Density is mass per volume.
D = M / V
D = (9.00 kg) / (0.100 m × 0.100 m × 0.100 m)
D = 9000 kg/m³
The correct answer is letter C. SWOT analysis. The cluster of decisions that managers make to assist the organization to achieve its goals is known as SWOT Analysis.
Here are the choices.A. Strategy B. Scenario planning C. SWOT analysis D. Diversification E. Related diversification
Answer:
A basic quantity is basically the physical quantity that can not be defined in terms of other quantities.
Explanation:
A basic quantity is basically the physical quantity that can not be defined in terms of other quantities.
Some of the names of the basic quantities include:
- Mass, denoted by the symbol 'm', with S.I. unit 'kg'
- Length, denoted by symbol 'l', with S.I. unit 'm'
- Time, denoted by symbol 't', with S.I. unit 's'
- Current, denoted by 'I', with S.I. unit 's' 'A'
- Temperature, denoted by 'T', with S.I. unit 'K'
- Amount of substance, denoted by 'n', with S.I. unit 'mol'
- Luminous Intensity, denoted by 'Iv', with S.I. unit 'cd'
- A basic quantity is chosen arbitrarily.
Answer:
a)143.8 decays/minute
b)0.41 decays/minute
Explanation:
From;
0.693/t1/2 = 2.303/t log (Ao/A)
Where;
t1/2=half-life of C-14= 5670 years
t= time taken to decay
Ao= activity of a living sample
A= activity of the sample under study
a)
0.693/5670 = 2.303/1000 log(162.5/A)
1.22×10^-4 = 2.303×10^-3 log(162.5/A)
1.22×10^-4/2.303×10^-3 = log(162.5/A)
0.53 × 10^-1 = log(162.5/A)
5.3 × 10^-2 = log(162.5/A)
162.5/A = Antilog (5.3 × 10^-2 )
A= 162.5/1.13
A= 143.8 decays/minute
b)
0.693/5670 = 2.303/50000 log(162.5/A)
1.22×10^-4 = 4.61×10^-5 log(162.5/A)
1.22×10^-4/4.61×10^-5 = log(162.5/A)
0.26 × 10^1 = log(162.5/A)
2.6= log(162.5/A)
162.5/A = Antilog (2.6 )
A= 162.5/398.1
A= 0.41 decays/minute