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3 years ago

How is temperature related to the physical change of a substance

2 answers:

7 0

Physical conditions like temp and pressure affect state of matter. When thermal energy is added to a substance, it’s temp increases, which can change its state from solid to liquid(melting), liquid to gas(vaporization), or solid to a gas( sublimation)
Hope this helped!

Tanzania [10]3 years ago

6 0

Answer:

Temperature is a measure of the kinetic energy of particles in a substance. As temperature increases, the atoms or molecules in a substance gain energy. As temperature decreases, the particles lose energy. A change in the energy of particles causes a change in their arrangement. A change in the arrangement of particles can lead to a physical change.

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What does every magnet possess?

IRINA_888 [86]

Answer:

a North and South Pole :)

Explanation:

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3 years ago

Americium-241 is used in smoke detectors. It undergoes alpha decay with a half life of 432 years. The alpha particles ionize som

babymother [125]

Answer:

860.6 years.

Explanation:

The parameters given are;

Initial detector activity = 370000 alpha decays per second

Final detector activity = 93000 alpha decays per second

Formula for time to change in activity is given by the following relation;

$t_{93000} = \dfrac{-ln\dfrac{A}{A_0} }{\lambda} = \dfrac{-ln\dfrac{93000}{370000} }{5.08 \times 10^{-11}} = 2.72 \times 10^{10} \, seconds$

t₉₃₀₀₀ = 2.72 × 10¹⁰ seconds = 860.6 years.

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3 years ago

An occupant of a car can survive a crash if the deceleration during the crash is less than 30 g. Calculate the force on a 64 kg

forsale [732]

The force on a 64 k person decelerating on that rate would be :

F = ma

F = 64 kg x 30 x 9.8

= 18816 N

Hope this helps

6 0

3 years ago

A constant voltage is applied across a circuit element. If the resistance of the element is doubled, what is the effect on the p

miv72 [106K]

Answer:

The power dissipated is reduced by a factor of 2

Explanation:

The power dissipated by a resistor is given by:

$P=I^2 R$

where

I is the current

R is the resistance

by using Ohm's law, $I=\frac{V}{R}$ , we can rewrite the previous equation in terms of the voltage applied across the resistor (V):

$P=(\frac{V}{R})^2R=\frac{V^2}{R}$

In this problem, the resistance of the element is doubled, while the voltage is kept constant. So we have $R'=2R$ while V remains the same; substituting into the formula, we have:

$P'=\frac{V^2}{2R}=\frac{1}{2}\frac{V^2}{R}=\frac{P}{2}$

so, the power dissipated is reduced by a factor 2.

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3 years ago

A ball is dropped from the top of a building. When does the ball have the most potential energy?

exis [7]

Answer:

When it hits the ground

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3 years ago