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3 years ago

2. The stage choreography for a play requires an

Physics

1 answer:

Leya [2.2K]3 years ago

4 0

Answer:

Explanation:

Given that the actor walk 5 steps forward, 9 steps left, and 2 steps backward to be standing over the trap

door.

Let first consider the steps forward and the steps backwards

The displacement = 5 - 2 = 3

That is, 3 steps forward.

Therefore,

The components of the actor's

motion from the starting position will be:

9 steps left and 3 steps forward

D is the correct answer.

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Question 4 (18 marks) (a) During a Physics Lab experiment, 1 st year SFY students analyzed the behavior of capacitors by connect

Nataly_w [17]

Answer:

1.) 274.5v

2.) 206.8v

Explanation:

1.) Given that In one part of the lab activities, students connected a 2.50 µF capacitor to a 746 V power source, whilst connected a second 6.80 µF capacitor to a 562 V source.

The potential difference and charge across EACH capacitor will be

V = Voe

Where Vo = initial voltage

e = natural logarithm = 2.718

For the first capacitor 2.50 µF,

V = Vo × 2.718

746 = Vo × 2.718

Vo = 746/2.718

Vo = 274.5v

To calculate the charge, use the below formula.

Q = CV

Q = 2.5 × 10^-6 × 274.5

Q = 6.86 × 10^-4 C

For the second capacitor 6.80 µF

V = Voe

562 = Vo × 2.718

Vo = 562/2.718

Vo = 206.77v

The charge on it will be

Q = CV

Q = 6.8 × 10^-6 × 206.77

Q = 1.41 × 10^-3 C

B.) Using the formula V = Voe again

165 = Vo × 2.718

Vo = 165 /2.718

Vo = 60.71v

Q = C × 60.71

Q = C

4 0

3 years ago

The natural pH of sea water is?

zhannawk [14.2K]

Answer:

The natural pH of sea water is between 7.5 and 8.4 (Mildly Alkaline)

Hope this helps :)

Have a great day !

5INGH

Explanation:

5 0

4 years ago

Patricia stands on a hill at an angle of 30 degrees. there is enough friction to stop her from sliding down the hill. Which free

makvit [3.9K]

Correct free-body diagram is option A)

Explanation:

There are three forces acting on Patricia:

Her weight, which is the force of gravitational attraction exerted by the Earth on her, whose magnitude is $mg$ (where m= mass and g= acceleration of gravity). The direction of this force is vertically downward.
The normal force, exerted by the plane on Patricia, which acts always up perpendicular to the plane
The force of friction, which prevents Patricia from sliding. The force of static friction acts in the direction opposite to the direction of motion if the body is let moving: so here, the force of friction acts up along the plane (parallel to the plane)