<span>The first quartile (Q1) is defined as the middle number between the smallest number and the median of the data set.</span>
None of the offered choices is correct.
The correct equation is
.. a = (2s -2ut)/t^2 . . . . . . . . parentheses are required
Por determinante:
5...1...1
1...0...1 = 0 --> se o determinante for igual a 0, os pontos estarão alinhados.
3...3...1
calculando: (5 x 0 x 1 + 1 x 1 x 3 + 1 x 3 x 1) - (1 x 0 x 3 + 1 x 1 x 1 + 3 x 1 x 5) =
0 + 3 + 3 - 0 - 1 - 15 =
6 - 1 - 15 =
5 - 15 = - 10 --> como não deu zero, os pontos não estão alinhados.
The x coordinate of the vertex will be the average of the two zeros, here -3 and 5, so x=(-3+5)/2 = 1, f(1)=(1+3)(1-5) = -16.
Answer: (1, -16)
Let's do it some other ways. How about completing the square to turn f in to vertex form?
f(x) = (x+3)(x-5) = x² - 2x - 15 = (x² - 2x + 1) - 1 - 15 = (x-1)² - 16
and now we can read off (1, -16) as the vertex.
The other method is the vertex is x= - b/2a = - (-2)/2(1) = 1.
Three methods, same answer. Good.
