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Verizon [17]
3 years ago
13

The equation S=4πr2 is given for the surface area of a sphere. Determine the radius of the sphere with a surface area of 135. Ro

und answers to the nearest hundredth.
Mathematics
1 answer:
larisa86 [58]3 years ago
3 0

Answer:3.277 units

Step-by-step explanation:

Given

The surface area of a sphere is 135\ sq.units

The surface area of a sphere is given by

\Rightarrow S.A.=4\pi r^2

Putting values

\Rightarrow 135=4\times \frac{22}{7}\times r^2\\\\\Rightarrow r^2=\dfrac{135\times 7}{22\times 4}\\\\\Rightarrow r^2=10.738\\\Rightarrow r=\sqrt{10.378}=3.277\ units

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allsm [11]

Answer:

B

Step-by-step explanation:

If the point lies on the circle, the distance of the point to the center would be equivalent to the circle's radius since radius is defined as the distance from the center to any point of the circle.

Since length of a radius is half of a diameter,

radius= diameter ÷2

radius= 12 ÷2

radius= 6 units

Let's find the length between each points to see which is equal to 6 units, using the distance formula below.

distance =  \sqrt{(y1 - y2)^{2} +  {(x1 - x2)}^{2}  }

A. Distance between 2 points

=  \sqrt{ {(10 + 5)}^{2}  + ( - 2 + 6)^{2} }  \\  =  \sqrt{15 ^{2} +  {4}^{2}}  \\  =  \sqrt{241}  \\  = 15.524 \: units

(to 5 s.f.)

Since the distance is greater than 6 units, point A lies outside the circle.

B. Distance between 2 points

=  \sqrt{ {(10 - 4)}^{2} + ( - 2 + 2)^{2}  }  \\  =  \sqrt{ {6}^{2} }  \\  = 6 \: units

Since the distance of B from the center is 6 units, point B lies on Circle O.

Let's check the other 2 points:

C. Distance between 2 points

=  \sqrt{ {(10 - 4)}^{2}  +  {( - 2 - 6)}^{2} }  \\  =  \sqrt{ {6}^{2}  + ( - 8)^{2} }  \\  =  \sqrt{100}  \\  = 10 \: units

Since the distance of point C from the center is greater than 6 units, point C lies outside the circle.

D. Distance between 2 points

=  \sqrt{ {(10 - 8)}^{2}  +  {( - 2 - 8)}^{2} }  \\  =  \sqrt{2^{2}  + ( - 10)^{2} }  \\  =  \sqrt{104}  \\  = 10.198 \: units

(to 5 s.f.)

Point D also lies outside Circle O.

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3 years ago
If a car goes from 60 miles per hour to 10 miles per hour in 5 seconds, find its acceleration. Enter your answer as a whole numb
denis-greek [22]

Answer:

a=-4.47\ m/s^2

Step-by-step explanation:

Given that,

Initial speed of a car, u = 60 mph = 26.82 m/s

Final speed of a car, v = 10 mph = 4.47 m/s

Time, t = 5 s

We need to find the acceleration of the car. The rate of change of velocity is called the acceleration of an object. It can be given by :

a=\dfrac{v-u}{t}\\\\a=\dfrac{4.47 -26.82 }{5}\\\\a=-4.47\ m/s^2

So, the acceleration of the car is 4.47\ m/s^2 and it is deaccelerating.

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3 years ago
What happens when you celebrate halloween in spring matrix multipication
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Answer:

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Step-by-step explanation:

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3 years ago
A pole 11 feet tall is used to support a guy wire for a tower, which runs from the tower to a metal stake in the ground. After p
Juliette [100K]

The given question is on trigonometry which requires the application of required <em>function</em> so as to determine the <em>value known</em>. So that the <u>length</u> of the guy wire is 67.0 feet.

<em>Trigonometry </em>is an aspect of mathematics that requires the application of some <u>functions</u> to determine the <em>value</em> of an unknown quantity.

Let the <u>length</u> of the guy wire be represented by l, and the angle that the guy wire makes with the <u>stake</u> be θ. So that applying the appropriate trigonometric function to determine the <em>value</em> of θ, we have:

Tan θ = \frac{opposite}{adjacent}

          = \frac{11}{4}

Tan θ = 2.75

θ = Tan^{-1} 2.75

  = 70.0169

θ = 70^{o}

Considering triangle formed by the <u>tower</u> and the <u>stake</u> to determine the value of l, we have;

Cos θ = \frac{adjacent}{hypotenuse}

Cos 70^{o}  = \frac{23}{l}

l = \frac{23}{Cos 70^{o} }

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l = 67.2515

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The <u>length</u> of the guy wire is 67 feet.

For more on trigonometric, check: brainly.com/question/6459892

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sasho [114]

here's the answer to your question

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3 years ago
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