Answer:
0.0594 = 5.94% probability of rain on November 1 and 2, but not on November 3.
Step-by-step explanation:
Rain on November 1:
0.9 of 0.6(rain on Oct 31).
0.3 of 0.4(not rain on Oct 31).
Rain on November 2:
Considering rain on November 1, 0.9 probability of rain.
Rain on November 3:
Considering rain on November 2, 0.1 probability of rain.
Find the probability of rain on November 1 and 2, but not on November 3.
Multiplicating the probabilities:
![p = (0.9*0.6+0.3*0.4)*0.9*0.1 = 0.0594](https://tex.z-dn.net/?f=p%20%3D%20%280.9%2A0.6%2B0.3%2A0.4%29%2A0.9%2A0.1%20%3D%200.0594)
0.0594 = 5.94% probability of rain on November 1 and 2, but not on November 3.