Answer:
t=5.5080( to 3 d.p)
Step-by-step explanation:
From the data given,
n =20
Deviation= 34/20= 1.7
Standard deviation (sd)= 1.3803(√Deviation)
Standard Error = sd/√n
= 1.3803/V20 = 0.3086
Test statistic is:
t = deviation /SE
= 1.7/0.3086 = 5.5080
ndf = 20 - 1 = 19
alpha = 0.01
One Tailed - Right Side Test
From Table, critical value of t =2.5395
Since the calculated value of t = 5.5080 is greater than critical value of t = 2.5395, the difference is significant. Reject null hypothesis.
t score = 5.5080
ndf = 19
One Tail - Right side Test
By Technology, p - value = 0.000
Since p - value is less than alpha , reject null hypothesis.
Conclusion:
From the result obtained it can be concluded that ,the data support the claim that the mean rating assigned to the wine when the cost is described as $90 is greater than the mean rating assigned to the wine when the cost is described as $10.
Answer:
7
Step-by-step explanation:
Let the each leg be x so,
√(x²+x²)=√98
or, √(2x²)=√98
or, x√2=7√2
or, x=7
If we have two points;
A(x₁,y₁)
B(x₂,y₂)
m=slope
m=(y₂-y₁) / (x₂-x₁)
Therefore:
(6,7)
(9,2)
m=(2-7) / (9-6)=-5/3.
Solution₁= the solpe of the line that passes through the poitns (6,7) and (9,2) is m=-5/3.
(17,9)
(5,29)
m=(29-9) / (5-17)=20/-12=-5/3
Solution ₂: the slope of the line that passes through the parir of points (17,9) and (5,29) is m=-5/3
Therefore, both lines have the same slope.
Answer:
5
Step-by-step explanation:
