While a match burns what type of change occurs?

What net force must act on the book to make it accelerate to the left at a rate

Nata [24]

Answer:

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Explanation:

3 0

3 years ago

write equations to show the chemical processes which occur when the first ionization and the second ionization energies of lithi

diamong [38]

Answer:

First ionization of lithium:

$\text{Li}\;(g)\to \text{Li}^{+} \; (g) + \text{e}^{-}$ .

Second ionization of lithium:

$\text{Li}^{+}\;(g) \to\text{Li}^{2+} \;(g) + \text{e}^{-}$ .

Explanation:

The ionization energy of an element is the energy required to remove the outermost electron from an atom or ion of the element in gaseous state. (Refer to your textbook for a more precise definition.) Some features of the equation:

Start with a gaseous atom (for the first ionization energy only) or a gaseous ion. Write the gaseous state symbol $(g)$ next to any atom or ion in the equation.
The product shall contain one gaseous ion and one electron. The charge on the ion shall be the same as the order of the ionization energy. For the second ionization energy, the ion shall carry a charge of +2.
Charge shall balance on the two sides of the equation.

First Ionization Energy of Li:

The products shall contain a gaseous ion with charge +1 $\text{Li}^{+}\;(g)$ as well as an electron $\text{e}^{-}$ .
Charge shall balance on the two sides. There's no net charge on the product side. Neither shall there be a charge on the reactant side. The only reactant shall be a lithium atom which is both gaseous and neutral: $\text{Li}\;(g)$ .

Hence the equation: $\text{Li}\;(g) \to \text{Li}^{+}\;(g) + \text{e}^{-}$ .

Second Ionization Energy of Li:

The product shall contain a gaseous ion with charge +2: $\text{Li}^{2+}\;(g)$ as well as an electron $\text{e}^{-}$ .
Charge shall balance on the two sides. What's the net charge on the product side? That shall also be the charge on the reactant side. What will be the reactant?

The equation for this process is $\text{Li}^{+} \; (g) \to \text{Li}^{2+}\;(g) + \text{e}^{-}$ .

5 0

3 years ago

A sample of nitrogen gas has a volume of 578 mL and a pressure of 124.1 kPa. What volume would the gas occupy at 80.2 kPa if the

Nataly_w [17]

Answer:

V2 = 894.4mL

Explanation:

P1= 124.1, V1= 578mL, P2 = 80.2kPa, V2= ?

Applying Boyle's law

P1V1 = P2V2

Substitute and simplify

124.1*578=80.2*V2

V2= 894.4mL

4 0

3 years ago

An adiabatic Turbine has R-134a as the working fluid. The inlet has a pressure of 200 kPa and a temperature of 20°C while the ou

Reptile [31]

Hey there!:

Detailed solution is shown below ask if any doubt :

3 0

3 years ago

Draw the Lewis structures of the molecules below and use them to answer the following questions:

Gnesinka [82]

Answer:

If NO₂ molecule written is for Nitrogen dioxide, then, four of the five molecules presented above have no dipole moment and only one of the five molecules, Ozone (0₃), has a dipole moment.

But if the NO₂ molecule is for nitrite ion, NO₂⁻, then three out of the five molecules presented have no dipole moment and only the Nitrite ion, NO₂⁻, and Ozone, 0₃, have dipole moments.

Explanation:

- The Lewis Structure for the molecules are drawn in the image attached to this answer.

The bond dipole moment uses the idea of electric dipole moment to measure the polarity of a chemical bond within a molecule. It occurs whenever there is a separation of positive and negative charges. Polarity occurs due to differences in electronegativity.

1) Browne or Trihydridoboron, BH₃ - No dipole moment in the molecule.

Each B-H bond in BH₃ is polar/forms a dipole because the B and H atoms have different electronegativities. But, the shape of the molecule is trigonal planar which is symmetrical, so the dipoles/bond polarities cancel. The resulting BH₃ molecule is non-polar.

2)Nitrogen dioxide, NO₂ has no dipole moment.

Nitrite ion, NO₂⁻ -> Has a dipole moment.

There are two NO₂ molecules, the Nitrogen dioxide molecule is linear and has no dipole moment, but the NO₂⁻ ion is a polar molecule. The geometry of the molecule is bent because of a non-bonding pair of electrons. The bent geometry causes the polarity and subsequent dipole moment.

3) Sulfur hexafluoride, SF₆ - no dipole moment.

Sulfur hexafluoride, abbreviated as SF₆, is a nonpolar molecule. SF₆ has an octahedral molecular geometry, which means that the sulfur molecule has six fluorine atoms surrounding it. While each individual bond is polar, there is no net effect as symmetrical nature of this octahedral molecular structure means the dipole moments all cancel out, meaning that the molecule is nonpolar.

4) Ozone, O₃ - has a dipole moment.

O₃ is polar because there are 18 valence electrons, so the lewis structure would position the central O connected to one single bond and one double bond to connect the other O's. The lone pair on the central O would also mean the molecule was bent, thus making it polar. Therefore, Ozone is a polar molecule with a dipole moment of 0.53 D. The molecule can be represented as a resonance hybrid with two contributing structures, each with a single bond on one side and double bond on the other.

5) Phosphorus pentachloride, PCl₅

PCl₅ has a symmetrical geometry, the vector sum of the dipole moments of the different P-Cl bonds cancel each other. Therefore, the overall dipole moment of PCl₅ becomes 0.

Hope this helps!

6 0

3 years ago